Answer:
The correct approach is Option B (Peer Review).
Explanation:
- Rather made reference to someone as a scientific peer-review, it encourages the specialist who has not been essential to the study team to analyze the study objectively and pointed out everyone's mistakes. It serves as major self-regulation for scholars and aims to make the publishing process somewhat credible. Hence, the solution to this issue is Peer Examination.
- Funding organizations rarely have the capabilities to recognize out mistakes, whereas definitive analysis is a method of study that helps to make a definitive statement. The gathering of data is simply a process of scientific study.
Other approaches do not apply to the example mentioned. Although the one mentioned is right.
I didn't see any statements, but here are some similarities of those elements:
They all have the same number of valence electrons, they will become cations, they all will lose 2 electrons, they will behave similarly in chemical reactions, they have similar chemical properties, they all are in the alkaline earth metal family. Hope this helps! :)
Answer:
Between -195°C to -215°C
Explanation:
We begin from this data:
P under -220°C will be solid, because -220°C is the freezing point.
Above -220°C, P will be at liquid state.
Then -185°C is the boling point, so above that temperature we have P as a gas.
Between -175°C to -210°C
Above -185°C we said that P is gas, so at -175°C P is not liquid. This state is F.
Between – 190°C to -225°C
At -190°C, we can have P as liquid, but -225°C is under -220°C, where P changes from liquid to solid. Then, this state is also F.
Between -200°C to -160°C
Above -185°C we said that P is gas, so at -160°C P is not liquid. This state is also F. The same, as the first situation.
Between -195°C to -215°C
-195°C is a lower temperature than -185°C. P is still liquid, we did not get the boiling point yet. -215°C is higher than -220°C, P is also liquid. There are still 5°C until P completely freezes. <em>This is the correct choice.</em>
Answer:
2 is your answer dude........
Explanation:
60.010=60.01
Answer:
Ch4 G +2o2 g co2 G +2h2o g How many moles of methane are required to produce 22 g co2 G after combustion
Explanation:
it's 22 grams..
hope the answer was helpful ....
