All categories

3 years ago

How many protons, electrons, and neutrons does an atom with atomic number 50 and mass number 125 contain?

1 answer:

5 0

The number of protons in an atom is equal the atomic number (= 50)

The sum of the Neutrons and Protons is the Atomic Mass (=125)
Neutrons + Protons=125

Plug in for the protons (50)
Neutrons +(50)=125

Then, once solved, we have Neutrons = 75

Assuming the atom is NOT an ion, the amount of electrons is equal to the number of protons. (protons=electrons=50=50)

Therefore:
There are 50 electrons, 50 protons, and 75 electrons.

You might be interested in

About the instruction that marko gave to hinano

Elden [556K]

Answer: he gave him a map of somewhere

Explanation:

3 0

3 years ago

In the laboratory, Austin is given a mixture of iron filings, sand, and salt. To separate the mixture, Austin uses a magnet, boi

Alex_Xolod [135]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4

Helga [31]

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

27+31+16(4)
58+48
106u

Moles of AlPO_4

61µg/106
0.000061/106
5.75×10^{-7}
57.5µmol

Moles of Al3+=57.5µmol

3 0

2 years ago

g Enter your answer in the provided box. If 30.8 mL of lead(II) nitrate solution reacts completely with excess sodium iodide sol

Ronch [10]

Answer:

$M=0.0637M$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$Pb(NO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaNO_3(aq)$

Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:

$n_{Pb^{2+}}=0.904gPbI_2*\frac{1molPbI_2}{461gPbI_2}*\frac{1molPb(NO_3)_2}{1molPbI_2} *\frac{1molPb^{2+}}{1molPb(NO_3)_2} =1.96x10^{-3}molPb^{2+}$

Finally, the resulting molarity in 30.8 mL (0.0308 L):

$M=\frac{1.96x10^{-3}molPb^{2+}}{0.0308L}\\ \\M=0.0637M$

Regards.

3 0

3 years ago

In the past mining companies were not made responsible for the clean-up of any of the mine sites. As a result, abandoned mines h

Andre45 [30]

Answer:

Old and inefficient mining smokestacks contaminate the soils around abandoned mine sites.

Explanation:

A smokestack, is a very tall channel commonly used in many instances to release gases produced by combustion processes directly into the air. These high towers are aimed at dispersing the gaseous pollutants over a wider area thereby minimizing their impact.

Old and inefficient smokestack do not contaminate the soil since they are very high towers that discharge gases directly into the atmosphere. Hence they are not part of the sources of soil contamination in abandoned mines.

4 0

3 years ago