Answer:
The pH of the final solution is 7.15
Explanation:
50 mL of 2.0 M of 
and 25 mL of 2.0 M of 
were mixed to make a solution
Final volume of the solution after dilution = 200 mL
Final concentration of ![K_2HPO_4, [K_2HPO_4] = \frac{50 mL\times 2 M}{200 mL} = 0.5 M](https://tex.z-dn.net/?f=K_2HPO_4%2C%20%5BK_2HPO_4%5D%20%3D%20%5Cfrac%7B50%20mL%5Ctimes%202%20M%7D%7B200%20mL%7D%20%3D%200.5%20M)
Final concentration of![KH_2PO_4, [KH_2PO_4] = \frac{25 mL\times 2 M}{200 mL} = 0.25 M](https://tex.z-dn.net/?f=KH_2PO_4%2C%20%5BKH_2PO_4%5D%20%3D%20%5Cfrac%7B25%20mL%5Ctimes%202%20M%7D%7B200%20mL%7D%20%3D%200.25%20M)
We use Hasselbach- Henderson equation:
![pH = pK_a+ log \frac{[salt]}{[acid]}pka of KH_2PO_4 = 6.85](https://tex.z-dn.net/?f=pH%20%3D%20pK_a%2B%20log%20%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7Dpka%20of%20KH_2PO_4%20%3D%206.85)
Substituting the values:
Therfore, the pH of the final solution is 7.15
Displaced volume:
final volume - <span>initial volume
1 mL = 1 cm</span>³<span>
38.5 mL - 35.0 mL = 3.5 cm</span>³
hope this helps!
Answer:
4 hours and 30 minutes
Explanation: because first wave was 1:30:00 and the second is 1:34:30
1:30:00 goes into 1:34:30 4 hours and 30 minutes.
Answer:
Cu(NO3)2 --> MM187.5558
NiNO3 *COEF2* --> 120.6983
