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horsena [70]
3 years ago
10

Ethan has 31 presents Alissa has 22 more than Ethan how many presents does Alissa have

Mathematics
2 answers:
Bond [772]3 years ago
5 0
Alissa has 53 presents
FromTheMoon [43]3 years ago
3 0
Alissa has 53 presents
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that is the answer
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How do you create a model of 15% of 60
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If Josh has 3 pencils and loses 1. How many does he have left
klio [65]

Answer: 2

Step-by-step explanation:

It is like you a=have 3 pencils and you give 1 to your friend how many will you have?

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6 0
3 years ago
BRAINLIEST IF CORRECT PLEASE DONT ANSWER IF YOU DONT KNOW OR REPORTED 50 POINTS I NEED MY GRADES TO BE BETTER
weqwewe [10]

Answer:

B.166 11/12

Step-by-step explanation:

To handle this problem better, we can separate the fraction and integer portions to look at the whole situation better.

First, let's only look at the integers. Anthony flew up his drone 125 feet (translating to +125), allowed it to drop 14 feet (translating to -14), and then flew it up for 55 feet (translating to +55). Hence, only considering the integers, the total change in the drone's position would be (125 - 14 + 55) feet, which equates to 166 feet.

You'd probably have already noticed this answer is quite close to B. 166 11/12 feet, but let's keep on going for now.

On the fraction part, he flew his drone up 1/2 feet, allowed it to drop 1/3 feet, and then flew it up for 3/4 feet, translating to (1/2 - 1/3 + 3/4) feet.

Hence, after making all fractions share the same denominator, that same equation would change to (6/12 - 4/12 + 9/12) feet, which equals to 11/12 feet.

Finally, the total magnitude of the drone's position would be (166 + 11/12) feet, which is equal to B.166 11/12 feet.

Hope this helped!

6 0
3 years ago
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Suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
goblinko [34]

15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.

<h3>What is a permutation?</h3>

A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.

Now, 13P_{5}= 13!/(13-5)!

= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444

Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.

To learn more about the permutation visit:

brainly.com/question/1216161.

#SPJ1

3 0
2 years ago
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