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Rzqust [24]
3 years ago
5

When musicians tune their instruments, they listen for "beats" in the sound the instruments produce when matched to a standard p

itch. These beats are moments when the sound becomes louder, then softer, then louder again. Musicians adjust the pitch of their instruments until they do not hear any more beats in the tuning process. Which statements explain the phenomenon described in the scenario? Check all that apply. 1.The moments of loudness represent constructive interference. 2.The tuning process depends on diffraction. 3.The moments of softness represent destructive interference. 4.The beats are produced by reflections. 5.The instrument is tuned when the frequencies of the standard and the instrument align.
Physics
1 answer:
olganol [36]3 years ago
5 0

Answer:

1. The moments of loudness represent constructive interference.

3.The moments of softness represent destructive interference.

5. The instrument is tuned when the frequencies of the standard and the instrument align.

Explanation:

Beats are the periodic and repeating fluctuations heard in the intensity of a sound when two sound waves of very similar frequencies interfere with one another.

Constructive interference is the process whereby two waves of identical wavelength that are in phase form a new wave with an amplitude equal to the sum of their individual amplitudes.

In the case of musical instruments, the loudness is due to a wave of larger amplitude formed as a result of the constructive interference of two waves that are in phase

Destructive Interference is the interference of two waves of equal frequency and opposite phase, resulting in the formation of a wave of lesser amplitude or even total cancellation.

The softness in sound is due to the destructive interference of two waves in opposite phase.

When there is an alignment in the frequency of the standard and the instrument, the instrument is tuned

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A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu
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Answer:

n = 1.56 x 10¹⁷ electrons

Explanation:

First of all, we will calculate the current passing through wire:

I = \frac{q}{t}

where,

I = current = ?

q = charge = 9 mC = 0.009 C

t = time = 3.6 s

Therefore,

I = \frac{0.009\ C}{3.6\ s}\\\\I =  0.0025\ A = 2.5\ mA

Now, for the same current in 10 s time the charge will be:

q = It = (0.0025 A)(10 s)

q = 0.025 C

Now, the number of electrons can be given as:

q = ne\\\\n = \frac{q}{e}\\\\

where,

n = no. of electrons = ?

q = charge = 0.025 C

e = charge on single electron = 1.6 x 10⁻¹⁹ C

Therefore,

n = \frac{0.025\ C}{1.6\ x\ 10^{-19}\ C}

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8 0
3 years ago
Which sound wave-object interaction is used by animals in echolocation?
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What are political obstacles keeping wind turbine from being used?
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The inflexibility, variability, and relative unpredictability of wind power as a means for electricity production, are the most obvious barriers to an easy integration and widespread application of wind power." Thus, the uncertainty of the wind requires a system that is always available to replace all the electrical output created by the wind turbine system. In other words, it is too expensive to have wind turbines lying around that don't do anything.

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An RC circuit takes t = 2.5 ms to charge to 35% of its full charge after it weas connected to a battery, What is the total time
marin [14]

Answer: time taken to charge to 95%

t = -5.80[ln(1-0.95)]

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Explanation:

For an RC Charging circuit

Where Vs

Vc = Vs (1 - e^(-t/RC))

Vc/Vs = 1 - e^(-t/RC)

-t/RC = ln(1 - Vc/Vs)

t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)

Where ;

Vc = voltage across the capacitor

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To calculate the time constant k;

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k = -2.5/ln(1-0.35)

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t = 17.38ms

4 0
3 years ago
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