The experiments will involve two billiard balls of known masses, m₁ and m₂, and velocities u₁ and u₂. The two are allowed to collide and the velocities of the balls after the collision v₁ and v₂ are recorded.
The momentum before and after the collision is then calculated as follows:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
<h3>What is the statement of the law of conservation of momentum?</h3>
The law of the conservation of momentum states that the momentum before and after collision in a system of colliding bodies is conserved
The momentum of a body is calculated using the formula below:
Momentum = mass * velocity.
Hence, for the two billiard balls, the momentum before and after the collision is conserved.
Learn more about momentum at: brainly.com/question/1042017
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Active transport move molecules from low concentrations to high concentrations.
The solution for this problem is:
For 1st minimum, let m be equal to 1.
d = slit width
D = screen distance.
Θ = arcsin (m * lambda/ (d))
= 0.13934 rad, 7.9836 deg
y = D*tan (Θ)
y = 6.50 * tan (7.9836)
= 0.91161 m is the distance from the central maximum to the first-order minimum
A valve is a flap of tissue that prevents blood from flowing back
