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olga55 [171]
3 years ago
13

Which example does not describe a behavioral adaptation? A. A squirrel buries acorns to dig up and eat later. B. A honeybee does

a dance to tell the other bees where to find flowers. C. Grass stops growing during a drought and begins growing again when it rains. D. The spines of a cactus protect it from animals.
Physics
2 answers:
chubhunter [2.5K]3 years ago
6 0
The answer is B) A honeybee does a dance to tell the other bees where to find flowers.
Honeybees do not dance, first of all.
Second, that is not an adaptation. That is more like a message. An adaptation is changing to the environment to survive. This is not changing to the environment. They are just signaling the other bees.
A, C, and D are all adaptations. They change so that they can survive. They do a different method than usual.
~Deceptiøn
Crazy boy [7]3 years ago
3 0
A I believe is your answer
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You attach a 3.10 kg weight to a horizontal spring that is fixed at one end. You pull the weight until the spring is stretched b
dolphi86 [110]

Answer:

0.785 m/s

Explanation:

Hi!

To solve this problem we will use the equation of motion of the harmonic oscillator, <em>i.e.</em>

x(t) = A cos(\omega t )+B sin(\omega t) - (1)

\frac{dx}{dt}(t) = \omega (B cos(\omega t )- A sin(\omega t) - (1)

The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:

x(0) = 0.100

\frac{dx}{dt}(0) = 0

Since cos(0)=1 and sin(0) = 0:

x(0)=A

\frac{dx}{dt}(0) = -B\omega

We get

A =0.100\\B = 0

Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:

x(0.4) = - 0.100

Since

x(t) = 0.100 cos(\omega t)\\ -0.100=x(0.4)=0.100cos(\omega 0.4)

This is the same as:

-1 = cos(0.4\omega)

We know that cosine equals to -1 when its argument is equal to:

(2n+1)π

With n an integer

The first time should happen when n=0

Therefore:

π = 0.4ω

or

ω = π/0.4  -- (2)

Now, the maximum speed will be reached when the potential energy is zero, <em>i.e. </em>when the sping is not stretched, that is when x = 0

With this info we will know at what time it happens:

0 = x(t) = 0.100cos(\omega t)

The first time that the cosine is equal to zero is when its argument is equal to π/2

<em>i.e.</em>

t_{maxV}=\pi /(2\omega)

And the velocity at that time is:

\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\omega t_{maxV})\\\frac{dx}{dt}(t_{maxV} ) =- 0.100\omega sin(\pi/2)\\

But sin(π/2) = 1.

Therefore, using eq(2):

\frac{dx}{dt}(t_{maxV} ) = 0.100*\omega = 0.100\frac{\pi}{0.400} = \pi/4

And so:

V_{max} = \pi / 4 =0.785

6 0
3 years ago
Even though earth has ____ mass than the sun, the moon orbits earth because it much nearer to it.
kozerog [31]

Even though the Earth has less mass than the Sun, the moon orbits Earth because it’s much nearer to it.

<u>Explanation :</u>

The fact is that the Moon orbits both the Sun and the Earth. On looking at the orbit of the Moon, it orbits in the same manner the way Earth does, but in a Spiro graph pattern along with orbiting the Earth with a small wobble to it.  

Since the Sun has greater distance from the Moon as compared to the Earth (around 400 times), the gravity of Earth draws better impact on the Moon.  

The escape velocity of the Moon is about 1.2 km/s at the distance from the Earth which is not sufficient to get ripped away from the Earth.  

Hence, the moon orbits the Earth along with orbiting the Sun together with the Earth, but seems as if it only orbits the Moon.

3 0
3 years ago
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A flashlight bulb is connected to a square loop of wire that measures cm on a side as shown in the figure below. assume the bulb
LUCKY_DIMON [66]
Mmmmmmmm Ф↓⇄㏑㏒,,⇆↑aaaaaaa
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3 years ago
What are moana's hobbies
crimeas [40]
The movie? Or the book
4 0
3 years ago
Help !
Black_prince [1.1K]
First off, you need to know the weight of the projectile, lift and drag coefficients something like a high Reynolds number is preferred, then use the gravitational constant of 9.8 meters per second squared those would be a good start to get closer to your goal
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4 years ago
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