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Serjik [45]
3 years ago
5

A cylindrical drill with radius 1 is used to bore a hole through the center of a sphere of radius 3. Find the volume of the ring

shaped solid that remains. equation editorEquation Editor

Physics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

volume of the ring shaped solid that remains = 103.68

Explanation:

Detailed explanation and calculation is shown in the image below

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Answer : The specific heat of aluminum is, 0.90J/g^oC

Solution : Given,

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Final temperature = 125^oC

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Formula used :

Q= m\times c\times \Delta T

or,

Q= m\times c\times (T_{final}-T_{initial})

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m = mass of the substance

c = heat capacity of aluminium

T_{final} = final temperature

 T_{initial} = initial temperature

Now put all the given values in the above formula, we get the specific heat of aluminium.

677g= (10g)\times c\times (125-50)^oC

c=0.9026J/g^oC=0.90J/g^oC

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A is the answer to this question...
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Answer:

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1) How many pennies are in $3.24?<br> $ 3.34<br> pennies<br> 100 p= $1.00
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