Explanation:
It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is
and final temperature is
.
(a) We know that for a monoatomic gas, value of
is \frac{5}{3}[/tex].
And, in case of adiabatic process,
= constant
also, PV = nRT
So, here
= 350 K,
, and 
Hence, 

= 267 K
Also,
= 4.0 atm,
, and 


= 2.04 atm
Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.
(b) For diatomic gas, value of
is \frac{7}{5}[/tex].
As,
= constant
also, PV = nRT
= 350 K,
, and 


= 289 K
And,
= 4.0 atm,
, and 


= 2.27 atm
Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.
the answer is a!! its pretty simple I just read the graph.
Answer:
0.70046 m/s²
2.732862 N
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
m = Mass of yo-yo = 0.3 kg
R = Radius of rolling disk = 5.1 cm
r = Radius of rod = 1 cm
For a rolling disks the acceleration is given by

The acceleration of the yo-yo is 0.70046 m/s²
The tension in the string will be

The tension in the string is 2.732862 N