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3 years ago

A Rocket took 5 minutes to travel the 185 km. How fast did the Rocket travel in kilometers per minute (km/min)?

Physics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

The rocket travelled 37km per minute

Explanation:

185÷5=37

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The speed of light in air is 3.0 x 10^8 m/s. The speed of light in particular glass is 2.3 x 10^8 m/s. Use the information to de

olga_2 [115]

Answer:

33.61°

Explanation:

Refractive index is equal to velocity of the light 'c' in empty space divided by the velocity 'v' in the substance.

Or ,

n = c/v.

v is the velocity in the medium (2.3 × 10⁸ m/s)

c is the speed of light in air = 3.0 × 10⁸ m/s

So,

n = 3.0 × 10⁸ / 2.3 × 10⁸

n = 1.31

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 25.0° )

${\theta_r}$ is the angle of refraction ( ? )

${n_r}$ is the refractive index of the refraction medium (air, n=1)

${n_i}$ is the refractive index of the incidence medium (glass, n=1.31)

Hence,

$1.31\times {sin25.0^0}={1}\times{sin\theta_r}$

Angle of refraction = $sin^{-1}0.5536$ = 33.61°

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3 years ago

When does air become turbulent around a thrown ball?

kherson [118]

Answer: B (on the rough side)

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4 years ago

Drag the item from the item bank to its corresponding match.

tigry1 [53]

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3 0

3 years ago

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The eye of a hurricane passes over grand bahama island in a direction 60.0Â° north of west with a speed of 41.0 km/h. three hour

Ksivusya [100]

initial velocity is given as 41 km/h at 60 degree North of West

$v_i = -41 cos60\hat i + 41 sin60 \hat j$

$v_i = -20.5 \hat i + 35.5 \hat j$

After some time the velocity is given as

$v_f = 25 \hat j$

now we can find the acceleration

$a = \frac{v_f - v_i}{t}$

$a = \frac{25\hat j - (-20.5 \hat i + 35.5 \hat j)}{3}$

$a = 6.83 \hat i - 3.5 \hat j$

now the distance is given by

$d = v*t + \frac{1}{2} at^2$

$d = (-20.5 \hat i + 35.5 \hat j)*4.5 + 0.5*(6.83 \hat i - 1.5 \hat j)* 4.5^2$

$d = -92.25\hat i + 159.75\hat j + 69.15\hat i - 15.19\hat j$

$d = -23.1 \hat i + 144.56\hat j$

so the magnitude of distance is

$d = \sqrt{23.1^2 + 144.56^2} = 146.4 km$

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3 years ago

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The value of g is greater at the poles than at the equator why

babunello [35]

Answer:

because the gravitational pull is maximum at the poles and decreases as it comes down toward the equator.

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3 years ago