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3 years ago

Please help!!! I dont know how to do this

Mathematics

1 answer:

gladu [14]3 years ago

4 0

Really hard, buy I'll try to solve. um,since WX and YZ are perpendicular, you have to multiply since its a 90° right angle. I hoped I helped :) can I be brainliest it will make my day :)

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A population of flies, P, over a given amount of time, x, is modeled by the expression

ra1l [238]

Do you know what you are suppose to do first

7 0

3 years ago

An international company has 27,600 employees in one country. If this represents 34.8% of the company's employees, how many empl

stepan [7]

Answer:

The total number of employees are 79310 .

Step-by-step explanation:

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ value}$

As given

An international company has 27,600 employees in one country. If this represents 34.8% of the company's employees .

Part value = 27600

Percentage = 34.8%

Putting all the values in the formula

$34.8 = \frac{27600\times 100}{Total\ value}$

$Total\ value = \frac{2760000}{34.8}$

Total value = 79310 (Approx)

Therefore the total number of employees are 79310 .

7 0

3 years ago

In the figure shown the value of a is equal to

Vikentia [17]

Answer:

a = 7.2

Step-by-step explanation:

The figure has been re-labelled and attached to this response.

From the figure, the larger right triangle DAB and the small right triangle BCA are similar. This is because;

i. They have two corresponding congruent angles which are the right angle

and angle B

Therefore, we can say that;

$\frac{|DB|}{|BA|} = \frac{|AB|}{|BC|}$

$\frac{13}{a} = \frac{a}{4}$

Cross multiply

a x a = 13 x 4

a² = 52

a = √52

a = 7.2

Note: The figure showing the similar triangles has also been attached to this response.

6 0

3 years ago

2 candy bars cost $0.98. At this rate, how much do 5 candy bars cost? The total cost for five candy bars is?

klio [65]

Answer:

$2.45

Step-by-step explanation:

First divide the cost by number of items. you shall get $0.49

Now multiply the cost of 1 candy bar into 5 and you shall get $2.45.

6 0

3 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

Left part:

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Right part:

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago