Answer:
Full wave rectification flips the negative half cycle of the sine wave to positive so the result is two positive half cycles.
Explanation:
hope it helps a lil
Answer:
The percent elongation in the length of the specimen is 42%
Explanation:
Given that:
The gage length of the original test specimen 
= 50 mm
The final gage length 
= 71 mm
The area = 206 mm²
maximum load = 162,699 N
To determine the percent elongation in %, we use the formula:
The percent elongation in the length of the specimen is 42%
Answer:
Employees who use hand and power tools and who are exposed to the hazards of falling, flying, abrasive and splashing objects, or exposed to harmful dusts, fumes, mists, vapors, or gases must be provided with the appropriate equipment needed, including Personal Protective Equipment, to protect them from the hazard.
Explanation:
Answer:
A) True. I hope this helps
Known :
D = 12 in = 1 ft
L = 850 ft
Q = 5.6 cfs
hA = 750 ft
hB = 765 ft
PA = 85 psi = 12240 lb/ft²
Solution :
A = πD² / 4 = π(1²) / 4
A = 0.785 ft²
<u>Velocity of water :</u>
U = Q / A = 5.6 / 0.785
U = 7.134 ft/s
<u>Friction loss due to pipe length :</u>
Re = UD / v = (7.134)(1) / (0.511 × 10^(-5))
Re = 1.4 × 10⁶
(From Moody Chart, We Get f = 0.015)
hf = f(L / d)(U² / 2g) = 0.015(850 / 1)((7.134²) / 2(32.2))
hf = 10 ft
PA + γhA = PB + γhB + γhf
PB = PA + γ(hA - hB - hf)
PB = 12240 + (62.4)(750 - 765 - 10)
PB = 10680 lb/ft²
PB = 74.167 psi
