Answer:
the rate of heat loss is 2.037152 W
Explanation:
Given data
stainless steel K = 16 W
diameter (d1) = 10 cm
so radius (r1) = 10 /2 = 5 cm = 5 ×
radius (r2) = 0.2 + 5 = 5.2 cm = 5.2 ×
temperature = 25°C
surface heat transfer coefficient = 6 6 W
outside air temperature = 15°C
To find out
the rate of heat loss
Solution
we know current is pass in series from temperature = 25°C to 15°C
first pass through through resistance R1 i.e.
R1 = ( r2 - r1 ) / 4 × r1 × r2 × K
R1 = ( 5.2 - 5 ) / 4 × 5 × 5.2 × 16 ×
R1 = 3.825 ×
same like we calculate for resistance R2 we know i.e.
R2 = 1 / ( h × area )
here area = 4 r2²
area = 4 (5.2 × )² = 0.033979
so R2 = 1 / ( h × area ) = 1 / ( 6 × 0.033979 )
R2 = 4.90499
now we calculate the heat flex rate by the initial and final temp and R1 and R2
i.e.
heat loss = T1 -T2 / R1 + R2
heat loss = 25 -15 / 3.825 × + 4.90499
heat loss = 2.037152 W
Answer:
Explanation:
A tension or current expressed in cosine form and with a positive sign can be converted directly into a phasor. This is done by indicating the tension and the offset angle:
So:
You can sum the phasors simply using a calculator, however, let's do it manually:
Let's find the rectangular form of each phasor using the next formulas:
For
So:
For
So:
Hence:
Finally:
Answer:
y = 56
Explanation:
We label each of the given equations as follows;
4·x + 2·y = 20...(1)
-8·x - 3·y = 16...(2)
Therefore, we are given a simultaneous equation, question
We make 'x' the subject of both equations and equate the result to find the value of 'y' as follows;
For equation (1)
4·x + 2·y = 20
∴ x = (20 - 2·y)/4 = 5 - y/2
x = 5 - y/2
For equation (2), we have;
-8·x - 3·y = 16
∴ x = (16 + 3·y)/(-8) = -2 - 3·y/8
x = -2 - 3·y/8
Equating the two equations of 'x', gives;
5 - y/2 = -2 - 3·y/8
7 = y/2 - 3·y/8 = (4·y - 3·y)/8 = y/8
∴ 7 = y/8
y = 7 × 8 = 56
y = 56
Answer:
Presents the relevant parameters to be kept in mind when using the following types of motors: 1. AC induction motor 2. BLDC motor 3. Synchronous motorn
Explanation:
sorry
Elastic Potential Energy is zero detailed description is given below.
Explanation:
- It is the energy stored in stretched or compressed elastic materials. This also means that elastic potential energy is zero in objects that have not been stretched or compressed.
- To determine the gravitational potential energy of an object, a zero height position must first be arbitrarily assigned. Typically, the ground is considered to be a position of zero height. But this is merely an arbitrarily assigned position that most people agree upon. Since many of our labs are done on tabletops, it is often customary to assign the tabletop to be the zero height position. Again this is merely arbitrary. If the tabletop is the zero position, then the potential energy of an object is based upon its height relative to the tabletop. For example, a pendulum bob swinging to and from above the tabletop has a potential energy that can be measured based on its height above the tabletop. By measuring the mass of the bob and the height of the bob above the tabletop, the potential energy of the bob can be determined.
- Potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height. An object possesses elastic potential energy if it is at a position on an elastic medium other than the equilibrium position.
Since the gravitational potential energy of an object is directly proportional to its height above the zero position, a doubling of the height will result in a doubling of the gravitational potential energy. A tripling of the height will result in a tripling of the gravitational potential energy.