V₁=4.8 l
c₁=2.5 moles/l
c₀=6.0 moles/l
v₀-?
v(H₂O)-?
n(H₂SO₄)=v₁c₁=v₀c₀
v₀=v₁c₁/c₀
v₀=4.8·2.5/6=2.0 l
v(H₂O)=v₁-v₀
v(H₂O)=4,8-2.0=2.8 l
you need to take 2.0 liters of solution (6.0 M H₂SO₄) and 2.8 liters of water
Answer:- Van't hoff factor(i) for the unknown ionic compound is 2.77.
Solution:- Elevation in boiling point is a colligative property and the equation used for solving this type of problems is...
delta Tb = i x m x kb
where delt Tb is elevation in boiling point.
i is Von't hoff factor.
m is molality of the solution and kb is the molal elevation constant. It's value for water is 0.512.
Boiling point of solution is given as 103.4 degree C and we know that water boils at 100 degree C.
So, delta Tb = 103.4 - 100 = 3.4 degree C
molality is given as 2.4m.
Let's plug in the values...
3.4 = i x 2.4 x 0.512
i = 3.4/(2.4 x 0.512)
i = 2.77
Its also listing the atomic numbers and the mass numbers plus it also has the numbers for the next elements
Explanation:
Formula to calculate the atomic packing factor is as follows.
APF =
=
It is given that atomic radius is 0.123 nm and density of metal is 7.45 .
Hence, number of atoms will be calculated as follows.
No. of atoms = = 4
APF =
= 1.3905
Thus, we can conclude that atomic packing factor if the unit cell has a tetragonal symmetry is 1.3905.