Answer:
For the first equation, the work done would be 60 J, but if it is done with 30 N, it would have been 90 J.
Explanation:
it's actually pretty easy one you practice it for some time. W ( work done in joules ) = F ( force put onto the object in newtons ) * D ( distance traveled in meters ).
Adding thermal energy
Performing work on the system
Answer:
27 °C
Explanation:
BY the statement of the question it is clear that it is about an ideal gas - and hence if change in KE is about zero - then there will be no change of temperature.
So, answer is 27 °C
The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
Therefore, option A is correct option.
Given,
Mass m = 14g
Volume= 3.5L
Temperature T= 75+273 = 348 K
Molar mass of CO = 28g/mol
Universal gas constant R= 0.082057L
Number of moles in 14 g of CO is
n= mass/ molar mass
= 14/28
= 0.5 mol
As we know that
PV= nRT
P × 3.5 = 0.5 × 0.082057 × 348
P × 3.5 = 14.277
P = 14.277/3.5
P = 4.0794 atm
P = 4.1 atm.
Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
learn more about pressure:
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