Betty weighs 420 n and she is sitting on a playground swing seat that hangs 0.40 m above the ground. tom pulls the swing back an
1 answer:
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Answer:
Fringe width = 21 mm
Explanation:
Fringe width is given by the formula
here we know that
L = 4.0 m
d = 0.108 mm
now from above formula we will have
so fringe width on the wall will be 21 mm
Answer:
W(r,out) = 5.81 MW
= 86.1 %
Explanation:
we use here steam table for get value of h1, s1 etc
so use for 6MPa and 600 degree
Enthalphy of steam h1 = 3658.8 kJ/kg
Entropy of steam s 1 is = 7.1693 kJ /kg.K
and
for 50 kPa and 100 degree
Enthalphy of steam h2 = 2682.4 kJ/kg
Entropy of steam s2 is = 7.6953 kJ /kg.K
so we use here energy balance equation that is
..............1
put here value and we get m
m =
solve it we get
m = 5.156 kg/s
so by energy balance equation
m1 = m
2 + W(r,out)
W(r,out) = m(1 -
2)
W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)
W(r,out) =
W(r,out) = W(a,out) - m.To.(s1-s2) ........................2
put here value
W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)
W(r,out) = 5908.19 = 5.81 MW
and
second law deficiency is
=
..............................3
put here value
= \frac{5}{5.81}
= 86.1 %
The incline is frictionless, this means we can use the conservation of energy: the initial kinetic energy of the block
is converted into gravitational potential energy
where h is the height reached by the block as it stops. By equalizing the two formulas, we get
However, this is the maximum height reached by the block. The distance along the surface of the plane is given by:
is converted into gravitational potential energy
where h is the height reached by the block as it stops. By equalizing the two formulas, we get
However, this is the maximum height reached by the block. The distance along the surface of the plane is given by: