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Fed [463]
3 years ago
10

A tiger eats as much as 40 pounds if food at a time but it may go for several days without eating anything suppose a Siberian ti

ger in the wilds eats an average of 18 pounds of food per day how much will the tiger eat in 28 days if he eats the same amount of food each day
Mathematics
1 answer:
lilavasa [31]3 years ago
7 0
If I'm understanding this correctly:

Tiger consumes 18lb/day of food. If we want to calculate how much is consumed in 28 days, assuming that rate is consistent, the answer is 18*28 = 504lb of food.
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Your leg has an endpoint of A at the top of your thigh, and endpoint C at your ankle. Imagine the length of your entire leg (fro
Ludmilka [50]

Answer: 25 inches

Step-by-step explanation:

Let's imagine that this line is the leg     A______________B________C

                                                                          x                       11

                                                             |___________36____________|

From A to C = 36 inches

From B to C = 11 inches

To find A to B all we have to do is subtract the knee to ankle length (11) from total leg length (36), which 36 - 11 = 25 inches.

4 0
3 years ago
What is the standard form of 5 and 352,000
Tanya [424]
It is 4009.738/!;7 corrects
7 0
2 years ago
How many solutions does 6 -3x = 12 - 6x have?
AysviL [449]

Answer:

Step-by-step explanation:

6-3x=12-6x

Only one solution of  x=2

5 0
3 years ago
Use Laplace transform methods to solve the differential equation: The initial conditions are f(0) = 0 and <img src="https://tex.
Llana [10]

Answer:

Step-by-step explanation:

\frac{d^2 y}{dt^2} +12\frac{dy}{dt} +32y = 10e^{-2t} where f(x) is replaced by y

Take Laplace on both sides

s^2 Y -s(0)-0 +12s Y-0+32Y = \frac{10}{s+2} \\Y(s^2+12s+32) =  \frac{10}{s+2}\\Y =  \frac{10}{(s+2)(s+4)(s+8)}

We can resolve into partial fraction to get Y = L(y)

Let this equals

\frac{A}{s+2} +\frac{B}{s+4} +\frac{C}{s+8} \\10 = A(s+4)(s+8) + B(s+2)(s+8) +Cs+4)(s+2) \\

Solving we get

s=-9

24C = 10 or C =5/12

s=-2:  A=10/12=5/6

s=-4: B = -5/4

Taking inverse Laplace

y(t) = \frac{-5e^{-4t} }{4} + \frac{5e^{-8t} }{12} +\frac{-5e^{-2t} }{6}

6 0
3 years ago
There is 28 kg 750 g of sugar in a sack. How many tins of 500 g sugar can be filled using the sugar in the sack?
vovangra [49]

Answer:

Step-by-step explanation:

28 kg + 750 g = 28*1000 + 750

                          28000 + 750

                       = 28750 g

Number of sack = Total quantity of sugar ÷ quantity of sugar in a sack

                           = 28750 ÷ 500

                           =  57 sacks

6 0
2 years ago
Read 2 more answers
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