If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
38 Is it explain step by step
From the attached graphic:
e = c*h/wavelength therefore,
wavelength = c*h / e
wavelength = 299,792,458 * 6.62606957e-34 / 3.38x10^-19
wavelength = 5.8771e-7 meters
Answer:
x = 72
Step-by-step explanation:
2/3x + 6 = 1/2x + 1/4x
2/3x + 6 = 3/4x
3/4 - 2/3 = 1/12
6 = 1/12x
Multiply 6 by 12 to get x
x = 72
Step 1: Simplify both sides of the equation.
Step 2: Subtract 6x from both sides.
- 65x²+390x+585−6x=6x−6x
- 65x²+384x+585=0
For this equation: a=65, b=384, c=585
Step 3: Use quadratic formula with a=65, b=384, c=585
- x=−b±√b2−4ac/2a
- x=−(384)±√(384)2−4(65)(585)/
- 2(65)
- x=−384±√−4644/130
Therefore, There are no real solutions.
