See the diagram above. Which of the following is the best prediction of what would happen if you increased the distance in secti
on 1 of the diagram?
A. Energy would decrease
B. The frequency would increase
C. The amplitude would decrease
D. The wavelength would decrease
A. Energy would decrease
B. The frequency would increase
C. The amplitude would decrease
D. The wavelength would decrease
1 answer:
By the definition of wavelength, the answer is the letter D, the wavelength would decrease.
We can see in the diagram a wave motion.
A wave has some characteristics:
- Has an amplitude, the distance from 0 to the crest (highest point in the y-direction, point (3) in the figure) it would see in the figure as (2)
- Has wavelength, the distance between the crests.
- Has a trough, the lowest point in the y-direction.
Now, if we increase the distance of the crests, by the definition shown above, we will increase the wavelength.
Therefore, the answer is letter D, the wavelength would increase.
You can learn more about wave motion here:
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Answer:
T = 712.9 N
Explanation:
First, we will find the speed of the wave:
v = fλ
where,
v = speed of the wave = ?
f = frequency = 890 Hz
λ = wavelength = 0.1 m
Therefore,
v = (890 Hz)(0.1 m)
v = 89 m/s
Now, we will find the linear mass density of the wire:
where,
μ = linear mass density of wie = ?
m = mass of wire = 90 g = 0.09 kg
L = length of wire = 1 m
Therefore,
μ = 0.09 kg/m
Now, the tension in wire (T) will be:
T = μv² = (0.09 kg/m)(89 m/s)²
<u>T = 712.9 N</u>
Answer:
d) -4.0
Explanation:
The magnification of a lens is given by
where
M is the magnification
q is the distance of the image from the lens
p is the distance of the object from the lens
In this problem, we have
p = 50 cm is the distance of the object from the lens
q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct
Also, q is positive since the image is real
So, the magnification is