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Paha777 [63]
3 years ago
15

A bicyclist is travelling at 25 m/s when he begins to decelerate at -4m/s2 . How fast is travelling after 5 seconds

Physics
1 answer:
Umnica [9.8K]3 years ago
7 0

Initial velocity (Vi) = 25 m/s

acceleration (a) = -4 m/s^{2}

time interval (t) = 5 sec

let us assume that final velocity after 5 sec be Vf

As acceleration is constant, we can apply the the equation of motion with constant acceleration i.e. V_{f} = V_{i} + at

Hence, V_{f} = 25 +(-4)(5) = 25 -20 = 5 m/s

so, the velocity of bicyclist will be 5 m/s after 5 sec

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Answer:

P = VI = (IR)I = I2R

Explanation:

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This extra voltage means more power. So if you double the current your would double the power, but you also double the voltage which doubles the power again = 4x as much power. P = VI = (IR)I = I2R

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A characteristic in an experiment, such as how much food, how much space, how hot or how cold, is termed a ____________. (spelli
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.3.3: Populating a vector with a for loop. Write a for loop to populate vector userGuesses with NUM_GUESSES integers. Read integ
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Answer:

#include <iostream>

#include <vector>

using namespace std;

int main() {

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  vector<int> userGuesses(NUM_GUESSES);

  int i = 0;

int uGuess = 0;

for(i = 0; i <= userGuesses.size() - 1; i++){

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cout << endl;

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Explanation:

First inbuilt library were imported. Then inside the main( ) function, 3 was assigned to NUM_GUESSES meaning the user is to guess 3 numbers. Next, a vector was defined with a size of NUM_GUESSES.

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Assuming the accleration applied was constant, we have

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