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iVinArrow [24]
3 years ago
14

If half of 5 =3.If the same proportion holds, what is the value of 1/3 of 10?​

Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

4  

Step-by-step explanation:

If you're rounding up:

(2.5 --> 3)

(3.3 --> 4)

<em>(Let me know if I'm misunderstanding something)</em>

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Granny Smith was able to make 61.75 ounces of strawberry jelly
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Why is it important to use a device like a random number table in a simulation?
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I don’t think it’s the second or third one I’m narrowing it down to the first or maybe fourth

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The plan for the Thorne’s backyard play area, shaped like a trapezoid, is shown. The area of the play area is 286.56 square feet
lorasvet [3.4K]

The length of material needed for the border is the perimeter of the backyard play area

<h3>How to calculate the length of material needed </h3>

The area of the play area is given as:

Area = 286.56

The area of a trapezoid is calculated using:

Area = 0.5 * (L1 + L2) * H

Where L1 and L2, are the parallel sides of the trapezoid and H represents the height.

The given parameter is not enough to solve the length of material needed.

So, we make use of the following assumed values.

Assume that the parallel sides are: 25 feet and 31 feet long, respectively.

While the other sides are 10.2 feet and 8.2 feet

The length of material needed would be the sum of the above lengths.

So, we have:

Length = 25 + 31 + 10.2 + 8.2

Length = 74.4

Using the assumed values, the length of material needed for the border is 74.4 feet

Read more about perimeters at:

brainly.com/question/17297081

6 0
2 years ago
The width of a plant cell is approximately 0.00001276 meter. Use scientific notation to write the width of the plant cell. NEED
Ilya [14]
It would be 1.276 x 10(5) the exponent is 5 next to the 10
6 0
3 years ago
A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,734. Suppose that a
DENIUS [597]

Solution :

To claim to be tested is whether "the mean salary is higher than 48,734".

i.e. μ > 48,734

Therefore the null and the alternative hypothesis are

$H_0 : \mu = 48,734$

and $H_1 : \mu > 48,734$

Here, n = 50

$\bar x = 49,830$

s = 3600

We take , α = 0.05

The test statistics t is given by

$t=\frac{\bar x - \mu}{\frac{s}{\sqrt n}}$

$t=\frac{49,830 - 48,734}{\frac{3600}{\sqrt 50}}$

t = 2.15

Now the ">" sign in the $H_1$ sign indicates that the right tailed test

Now degree of freedom, df = n - 1

                                              = 50 - 1

                                              = 49

Therefore, the p value = 0.02

The observed p value is less than α = 0.05, therefore we reject $H_0$. Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.

3 0
3 years ago
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