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Answer:
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Explanation:
The free energy of the reaction is given by :
where,
= standard Gibbs free energy
R = Gas constant =
T = temperature in Kelvins
K = equilibrium constant
We have :

1 kJ = 1000 J
T = 37.0 C = 37 +273.15 K = 310.15 K
Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9
![\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]](https://tex.z-dn.net/?f=%5CDelta%20G%3D-16%2C700%20J%2Fmol%2B8.314J%2FK%20mol%5Ctimes%20310.15%20K%20%5Cln%5B21.9%5D)

The free energy change for the reaction at 37.0°C is -8.741 kJ.
Answer:
give us the choices please
Explanation:
Answer:
4.22 × 10 ⁻²² mol
Explanation:
Given data:
Number of molecules of bromine = 254 molecules
Number of moles = ?
Solution:
1 mole = 6.02 × 10 ²³ molecules
254 molecules × 1 mol / 6.02 × 10 ²³ molecules
42.2 × 10 ⁻²³ mol
4.22 × 10 ⁻²² mol