POH of a 0.0072 M=-lg(0.0072) = 2.1426675
Answer:
The molecular formula of glucose is C₆H₁₂O₆
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of smallest whole number of atoms.
Molecular formula:
It gives the total number of atoms in a molecule of compound.
The molecular formula and empirical formula can be related as follow:
Molecular formula = n × empirical formula
Given data:
Empirical formula = CH₂O
Molecular formula = ?
It is stated in given problem that molecular formula is the 6 times of the empirical formula.
Molecular formula = n × empirical formula
Molecular formula = 6 × CH₂O
Molecular formula = C₆H₁₂O₆
The molecular formula of glucose is C₆H₁₂O₆.
The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 1.25 mL
<u>Explanation:</u>
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of stomach acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the volume of HCl neutralized is 1.25 mL
