Answer:
A. Compounds
Explanation:
Firstly, don't let the word "pure" confuse you; this is pretty much irrelevant to the question.
The key to answering this question lies in "substance" and "more than one type of element chemically bonded."
Something you ought to memorize is that a substance is either an element or compound. Therefore, you can eliminate choices B./C.
Next, use the part of the definition that says "more than one type of element chemically bonded" to conclude that it's a compound. Not only is this the definition of a compound, but the fact that is says <em>more than one type of element</em> should automatically tell you that it is different from just a regular element (Choice D.).
<span>Out of the possible answers for this question, fluorine in the second period is correct. Of the four elements fluorine, chlorine, bromine and iodine, fluorine has the largest first ionization energy, with a Enthalpy number of 1681.0. Of all the elements, helium has the highest first ionization energy figure.</span>
Answer:

Explanation:
Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.
- m= 1.85 kg
- g= 9.8 m/s²
- h= 2.23 m
Substitute the values into the formula.

Multiply the first 2 numbers together.

Multiply again.

- 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
- Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

The textbook has <u>40.4299 Joules of potential energy.</u>
Answer:
2,3,6,1
2,3,6,1
Explanation:
The unbalanced reaction expression is given as:
AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.
aAlBr₃ + bK₂SO₄ → cKBr + dAl₂(SO₄)₃
Conserving Al; a = 2d
Br: 3a = c
K: 2b = c
S: b = 3d
O: 4b = 12d
Let a = 1, c = 3, d =
b =
Multiply through by 2 to give;
a = 2, b = 3, c = 6 and d = 1
2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃