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Tju [1.3M]
3 years ago
5

* ate: Find 8% of 40. nt)

Mathematics
2 answers:
olasank [31]3 years ago
3 0
The answer is 3.2.
natima [27]3 years ago
3 0
8 percent of 40 is 3.2
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Compare using &gt;, &lt;, or =.<br><br> 3 miles_5,000 yards
lina2011 [118]

Answer:

3 miles = 5280 yds

5280 yds > 5,000 yds

in this case 3 miles is greater than 5,000 yards

4 0
3 years ago
Show work / explain it ​
aivan3 [116]
Answer:
X 1 = -4,X 2 =12

EXPLANATION:

Determine the defined range
X+6/x=6/x-8,x#0,x#8

Simplify the equation using cross-multiplication
(X+6) x (x-8)=6x

Move variable to the left-hand side and change its sign
(X-6)x(x-8)-6x=0

Multiply the parentheses
X^2-8x+6x-48-6x=0

Since two opposites add up to zero, remove them from the expression
X^2-8x-48=0

Write -8x as a difference
X^2+4x-12x-48=0

Factor out x from the expression
Xx(x+4)-12x-48=0

Factor out -12 from the expression
Xx(x+4)-12(x+4)=0

Factor out from the expression
(x+4)x(x-12)=0

When the product of factors equals 0, at least one factor is 0
x+4=0
x-12=0

Solve the equation for x
X=-4
X-12=0
X=-4,x#0,x#8

Check if the solution is in the defined range
X=-4
x=12

The equation has 2 solutions

X 1 = -4,X 2 =12

Hope this helps


3 0
3 years ago
4d + 7e = 68<br> -4d - 6e = -72<br> QUICK
Alexxx [7]

Step-by-step explanation:

by adding :

e=_4

d=24.....

6 0
3 years ago
AB = 3 + x
strojnjashka [21]

Answer:

Option A) 4, 2

Step-by-step explanation:

We are given that quadrilateral ABCD is a  parallelogram with sides:

AB = 3 + x\\DC = 4x\\AD = y + 1\\BC = 2y

Since the opposite sides of a parallelogram are equal, we can write:

AB = DC\\AD=BC

Equating the sides we get,

\Rightarrow 3+x = 4x\\4x-x = 3\\3x = 3\\x = 1\\\Rightarrow y + 1 = 2y\\y = 1

Putting the values of x and y, we get:

AB = 3 + x =4\\DC = 4x =4\\AD = y + 1=2\\BC = 2y=2

Thus, the lengths of the opposite side pairs is 4,2.

4 0
3 years ago
Make a the subject of a2+b2=c2
wel

Answer:

a=\sqrt{c^2-b^2

⇒ a=\sqrt{(c+b)(c-b)}        [Factorized form]

Step-by-step explanation:

Given expression:

a^2+b^2=c^2

We need to make a the subject.

In order to do that we need to solve the expression for a in terms of b and c

We have,

a^2+b^2=c^2

Subtracting both sides by b^2

a^2+b^2-b^2=c^2-b^2

a^2=c^2-b^2

Taking square root both sides in order to remove square of a

\sqrt{a^2}=\sqrt{c^2-b^2}

a=\sqrt{c^2-b^2

The difference of squares can be factorized and written  as:

a=\sqrt{(c+b)(c-b)}    [difference of squares x^2-y^2=(x+y)(x-y) ]

4 0
3 years ago
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