Answer:
False
Explanation:
it is very rare to get hyposmia
Answer:
Speed of air = 1106.38 ft/s
Explanation:
Speed of sound in air with temperature

Here speed is in m/s and T is in celcius scale.
T = 50°F

Substituting

Now we need to convert m/s in to ft/s.
1 m = 3.28 ft
Substituting

Speed of air = 1106.38 ft/s
The strength of electric field E is 17 N / C.
<u />
<u>Explanation:</u>
Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by
E = F / q
where E represents the electric field strength,
F represents the force in newton,
q represents the charge in coulomb.
Given the charge q = 0.30 coulombs
force F = 5.0 N
Electric field strength E = force / charge
= 5.0 / 0.30
E = 16.66 = 17 N / C.
Answer:37 J
Explanation:
Given
Step :1
Heat added Q=44 J
Work done=-20 J

Step :2
Heat added Q=-61 J
work done 



as the process is cyclic


work done in compression is 37 J