Answer:
Watershed should be your answer!
Opening the valve allows more of the pressurized material out. If the area is decreased, less of the pressurized material is released, and its force ends up more spread out, reducing the pressure. Opening the valve will increase volume of transfer of your liquid.
Answer:
The flow of energy from falling water to the steam is;
a) Mechanical → Mechanical → Electrical → Thermal → Thermal
Explanation:
1) Mechanical → Mechanical
The water in the pipe before it falls possesses potential energy which it converts into kinetic energy as it falls from height
2) Mechanical → Mechanical
The water falling from the pipe stream unto the turbine wheel transfers its kinetic (mechanical) energy due to its motion on to the turbine wheel to give the wheel rotational motion
3) Mechanical → Electrical
The kinetic (mechanical) energy from the rotating turbine wheel is converted into electrical energy in the electrical generator which transported through the electrical circuit
4) Electrical → Thermal
The electrical energy from the electric current is then converted into thermal energy as the current passes through the resistors in the heating filament
5) Thermal → Thermal
The heated filament transfers thermal energy to the the water in the beaker by conduction which raises the temperature of the water such that as the water acquires more thermal energy it turns into steam
Therefore, we have the flow of energy from the falling water to steam as follows;
1) Mechanical 2) Mechanical 3) Electrical 4) Thermal 5) Thermal
Answer:
11250 N/C
Direction: 0 deg counterclockwise from positive x-axis
Explanation:
= magnitude of charge on each particle = 5 μC = 5 x 10⁻⁶ C
= distance of each particle from center of circle = 2 m
= Magnitude of electric field at the center by each particle
Magnitude of electric field at the center by each particle is given as
inserting the values
From the diagram , we see that being equal and opposite, the electric fields due to charge q₁ and q₃ cancel out.
So net electric field at center is only due to charge q₂ direction towards positive x-direction
So
= Resultant electric field = 11250 N/C
Direction: 0 deg counterclockwise from positive x-axis
