2 years ago

What is the angle between P×Q and P±Q? 1) 0 2) PIE/2 3) PIE 4) 3PIE/2

Physics

1 answer:

faltersainse [42]2 years ago

5 0

Answer:

option 2 is correct

Explanation:

the angle between p*q and p+q is 90 degree which is equal to π/2

it is rule that product of two vectors is always perpendicular to the plane in which both the vector lie

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Answer:

33.6 m

Explanation:

Given:

v₀ = 0 m/s

a = 47.41 m/s²

t = 1.19 s

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Δx = (0 m/s) (1.19 s) + ½ (47.41 m/s²) (1.19 s)²

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2 years ago

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2 years ago

What is the stretch when you pull with a force of 25 N on a spring with a spring constant of 8 N/m? *

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Hooke's Law

$\tt F=k.\Delta x$

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x = stretch

F = force

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$\tt \Delta x=\dfrac{F}{k}=\dfrac{25}{8}=3.125\rightarrow 3.13\:m$

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1 year ago

Which property of a substance is not affected by physical changes?

Leokris [45]

The answer is A. Reactivity

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3 years ago

Determine the amount of work done by the engine of a car with a mass of 2500 kg when it accelerates from 45 mph to 65 mph. (Use

Y_Kistochka [10]

Answer:

amount of work done, W = 549.36 kJ

Given:

mass of a car engine, m = 2500 kg

initial velocity, u = 45 mph

final velocity, v = 65 mph

1 mile = 1609

Solution:

We know that 1 hour = 3600 s

Now, velocities in m/s are given as:

u = 45 mph = $\frac{45\times 1609}{3600}$ = 20.11 m/s

v = 65 mph = $\frac{65\times 1609}{3600}$ = 29.05 m/s

Now, the amount of work done, W is given by the change in kinetic energy of the car and is given by:

W = $\frac{1}{2}m\Delta v^{2}$

W = $\frac{1}{2}m\times (v^{2} - u^{2})$

W = $\frac{1}{2}2500\times (29.05^{2} - 20.11^{2})$

W = 549.36 kJ

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2 years ago