The complete question is;
A circular coil consists of N = 410 closely winded turns of wire and has a radius R = 0.75 m. A counterclockwise current I = 2.4 A is in the coil. The coil is set in a magnetic field of magnitude B = 1.1 T.
a. Express the magnetic dipole moment μ in terms of the number of the turns N, the current I, and radius
R.
b. Which direction does μ go?
Answer:
A) μ = 1738.87 A.m²
B) The direction of the magnetic moment will be in upward direction.
Explanation:
We are given;
The number of circular coils;
N = 410
The radius of the coil;R = 0.75m
The current in the coils; I = 2.4 A
The strength of magnetic field;
B =1.1T
The formula for magnetic dipole moment is given as;
μ = NIA
Where;
N is number of turns
I is current
A is area
Now, area; A = πr²
So, A = π(0.75)²
Thus,plugging in relevant values, the magnetic dipole moment is;
μ = 410 * 2.4 * π(0.75)²
μ = 1738.87 A.m²
B) According to Fleming's right hand rule, the direction of the magnetic moment comes out to be in upward direction.
Answer:
La rapidez con que el fármaco es absorbido en el torrente sanguíneo depende, en parte, del suministro de sangre al músculo: cuanto menor sea el aporte de sangre, más tiempo necesitará el fármaco para ser absorbido.
Para la administración por vía intravenosa se inserta una aguja directamente en una vena
Explanation:
Phosphorus = 2 atoms
Oxygen = 8 atoms
Barium = 3 atoms
Answer:
2.1×10¹⁸ C
Explanation:
Using,
E = kq/r²...................... Equation 1
Where E = Electric field, q = charge, r = distance, k = coulombs constant.
make q the subject of the equation
q = Er²/k.................. Equation 2
Given: E = 180000 N/C, r = 2.8 cm = 0.028 m
Constant: k = 9×10⁹ Nm²/C².
Substitute these values into equation 2
q = 180000(9×10⁹)/0.028²
q = 2.1×10¹⁸ C
Hence the object charge is 2.1×10¹⁸ C
They will hit and go through eachother
