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3 years ago

Which embedded molecule in the cell membrane moves large molecules into and out of the cell?

Physics

1 answer:

Nezavi [6.7K]3 years ago

5 0

The correct answer is A.

The cell membrane consists of a phospholipid bilayer with embedded proteins. Sometimes molecules are just too big to easily flow across the plasma membrane or dissolve in the water so that they can be filtered through the cell membrane. In these cases , the cells must put out a little energy to help get molecules in and out of the cell.

The proteins embedded in the plasma membrane form channels through which other molecules can pass. Some proteins act as carriers, that is they are 'paid" in energy to let a molecule attach to itself and then transport that molecule inside the cell. This is called active transport.

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Determine the magnitude of the effective value of g⃗ at a latitude of 60 ∘ on the earth. assume the earth is a rotating sphere.

dezoksy [38]

In addition to acceleration of gravity we experience centrifugal acceleration away from the axis of rotation of the earth. this additional acceleration has value ac = r w^2 where w = angular velocity and r is distance from your spot on earth to the earth's axis of rotation so r = R cos(l) where l = 60 deg is the lattitude and R the earth's radius and w = 1 / (24hr x 3600sec/hr)
<span>now you look up R and calculate ac then you combine the centrifugal acc. vector ac with the gravitational acceleration vector ag = G Me/R^2 to get effective ag' = ag -</span>

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3 years ago

When an object moves in uniform circular motion, the direction of its acceleration is?

Harrizon [31]

Clock wise idk i think you should double check my answer

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2 years ago

A player kicks a football from ground level with an initial velocity of 27.0 30.0 above the horizontal Find the ball's maximum h

stepladder [879]

Answer:

Given

initial velocity (u) =27.030

Force of gravidity g) =9.8

Rtc maximum height Hmix =?

$sln \\ \ hmix = u {}^{2} \div 2g \\ 27.030 \div 2 \times 9 \\ \\ hmix = 38.025m$

5 0

2 years ago

A 1.2-kg mass is projected from ground level with a velocity of 30 m/s at some unknown angle above the horizontal. A short time

Dmitriy789 [7]

Answer:

$K_f$ = 351.84 J

Explanation:

Using the conservation of energy K:

$E_i = E_f$

so:

$\frac{1}{2}mv^2 = K_f + mgh$

where m is the mass, v the initial velocity, $K_f$ is the kinetic energy of the mass as it clears the fence, g the gravity and h the altitude.

Then, replacing values, we get:

$\frac{1}{2}(1.2kg)(30m/s)^2 = K_f + (1.2kg)(9.8m/s^2)(16m)$

solving for $K_f$ :

$K_f$ = 351.84 J

3 0

3 years ago

You throw a ball into a box and close the lid. You hear the ball bouncing around inside as the ball’s energy changes from gravit

beks73 [17]

Answer:

Thermal energy.

Explanation:

We know that energy is conserved and it only transform one form to another form ,Like potential energy transform in to kinetic energy when a ball fall down from a height and obtain some velocity.

In this case energy changes from gravitational energy to kinetic energy then elastic energy and after some time this energy will convert in to thermal energy.

So the answer is thermal energy.

5 0

3 years ago