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labwork [276]
3 years ago
15

The tallest living man at one time had a height of 230 cm. The shortest living man at that time had a height of 91.3 cm. Heights

of men at that time had a mean of 170.53 cm and a standard deviation of 5.91 cm. Which of these two men had the height that was more​ extreme?
Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer: The shortest living man at that time had the height that was more​ extreme.

Step-by-step explanation:

We will z scores to solve this exercise. The formula we need is:

 z=\frac{x-\mu}{\sigma}

Where x is the raw score, \mu is the mean and \sigma is the standard deviation.

We know at that time heights of men had a mean of 170.53 centimeters and a standard deviation of 5.91 centimeters, then:

\u=170.53\\\\\sigma=5.91

Knowing that the tallest living man at that time had a height of 230 centimeters, we get:

z=\frac{230-170.53}{5.91}\approx10.07

And knowing that the shortest living man at that time had a height of 91.3 centimeters, we get:

z=\frac{91.3-170.53}{5.91}\approx-13.40

Based on this, we can conclude that the shortest living man at that time had the height that was more​ extreme.

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