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lianna [129]
3 years ago
9

5. A car is making a 12-mile trip. It travels the first 6.0 miles at 30 miles per hour and the last 6.0 miles at 60 miles per ho

ur. What is the car's average speed for the entire trip? A) 20 mph B) 35 mph C) 40 mph D) 45 mph E) 50 mph
Physics
1 answer:
stellarik [79]3 years ago
5 0

Answer:C

Explanation:

Given

Total distance covered by car d=12\ miles

First it travels d_1=6\ miles with v_1=30\ mph

then it travels d_2=6\ miles with v_2=60\ mph

time taken during first half t_1=\frac{d_1}{v_1}=\frac{6}{30}=0.2\ hr

time taken during Second half t_1=\frac{d_2}{v_2}=\frac{6}{60}=0.1\ hr

average speed v_{avg}=\frac{distance}{time}

v_{avg}=\frac{12}{0.2+0.1}=\frac{12}{0.3}=40\ mph

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Snezhnost [94]

Answer:

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Explanation:

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3 0
3 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed
kogti [31]

Answer:

a)y_{first}=5.3mm

b)y_{second}=10.6-5.3 =5.3 mm  

Explanation:

a)

The width of the central bright in this diffraction pattern is given by:

y=\frac{m\lambda D}{a} when m is a natural number.

here:

  • m is 1 (to find the central bright fringe)                
  • D is the distance from the slit to the screen
  • a is the slit wide
  • λ is the wavelength

So we have:

y_{first}=\frac{633*10^{9}*3.35}{0.0004}

y_{first}=5.3mm

b)

Now, if we do m=2 we can find the distance to the second minima.

y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}

y_{2}=10.6 mm

Now we need to subtract these distance, to get the width of the first bright fringe :

y_{second}=10.6-5.3 =5.3 mm    

I hope it heps you!

     

4 0
3 years ago
________ is the stress caused by forces that slip or slide one part of a material against another. a) Bending b) Shear c) Compre
jenyasd209 [6]
The best answer to fill in the blank would be B) Shear because shear stress is the process of where the composition of an object changes by sliding forces and so because of this, its a deformity.
8 0
4 years ago
©
atroni [7]

Answer:

ω = 0.1 rad/s

v = 0.002 m/s

Explanation:

The angular velcoity of the second hand of the clock can be found by:

ω = θ/t

where,

ω = Angular Speed

θ = Angular Displacement

t = time taken

Now, for one complete revolution of second hand of the clock:

θ = 2π rad

t = 60 s

Therefore,

ω = 2π rad/60 s

<u>ω = 0.1 rad/s</u>

Now, for the linear speed (V):

V = rω

where,

V = Linear Speed of Second Hand = ?

r = radius = length of second hand = 0.02 m

Therefore,

V = (0.02 m)(0.1 rad/s)

<u>V = 0.002 m/s</u>

5 0
3 years ago
A 0.60 kg rubber ball has a speed of 2.0 m/s at point A, and kinetic energy of 7.5 J at point
aliina [53]
<span>Let's first off calculate the kinetic energy using the formula 1/2MV^2. Where the mass, M, is 0.6Kg. And speed, V, is 2. Hence we have 1/2 * 0.6 * 2^2 = 1.2J. Since kinetic energy is energy due to motion; hence at point B the rubber has a KE of 1.2J and not 7.5J. So I would say that only the Mass and speed is actually true; While it's kinetic energy is not true.</span>
7 0
4 years ago
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