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Gwar [14]
3 years ago
14

Lenses can be found in a variety of objects which example does not have a lens?

Physics
2 answers:
Burka [1]3 years ago
4 0
Tbh ! All of them have lens but I would go with B.) Smart Phone 

Hope This Helps !!!
Aleksandr [31]3 years ago
4 0

Answer:

The correct option is B). Smart phone.

Explanation:

Consider the provided options:

Diving masks and night vision goggles have a lens.

Electron microscopes have electromagnetic lenses or electron optical lens systems.

Which means diving mask, electron microscope and night vision goggles have a lens.

Thus, the correct option is B). Smart phone.

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Peter notices that his eight-year-old daughter frequently mentions the unusual habits of a new boy, who is from a different cult
pickupchik [31]
The answer should be C. Encourage his daughter to make friends with the new boy.

Hope this helps and have a happy new year
6 0
3 years ago
Two objects, T and B, have identical size and shape and have uniform density. They are carefully placed in a container filled wi
Korvikt [17]

Complete Question:

Two objects, T and B, have identical size and shape and have uniform density. They are carefully placed in a container filled with a liquid. Both objects float in equilibrium. Less of object T is submerged than of object B, which floats, fully submerged, closer to the bottom of the container. Which of the following statements is true?

  • Object T has a greater density than object B.
  • Object B has a greater density than object T.
  • Both objects have the same density.  

Answer:

Object B has a greater density than object T

Explanation:

Any object partially or completely submerged in a liquid, experiments an upward force, equal to the weight of  the volume displaced by the liquid. This force is called the buoyant force, and can be expressed as follows:

Fb = ρl * Vs*g

where ρl is the density of the liquid, and Vs is the submerged volume.

This force must be compared with the weight of the object, which is always downward, and can be expressed as follows:

Fg = ρb* Vb * g

where ρb, is the density of the object, and Vb is the total volume of the object, regardless which portion is submerged.

For object B, as it floats fully submerged, this means that both forces are equal in magnitude:

Fg = Fb⇒ ρb* Vb * g = ρl * Vs*g

As Vb = Vs (the object is fully submerged) this means that ρb =ρl.

For object T, as it floats partially submerged, this means that Fg < Fb:

Fg= ρt* Vt * g < Fb = ρl * Vs*g.

Now, we know that ρb =ρl, so we can replace in the equation above:

ρT* Vt * g < ρb*Vs*g

Simplifying common terms, and replacing Vs by KVt (where K is the fraction of the total volume which is submerged, i.e. K<1), we have:

ρt*Vt < ρb*K*Vt ⇒ ρt / ρb < K < 1 ⇒ ρt < ρb ⇒ ρb > ρt

3 0
3 years ago
A NATO base in northern Norway is warmed with a heat pump that uses 7.0 °C ocean water as the cold reservoir. Heat extracted fro
tatiyna

Answer:

3.33, 4.84

Explanation:

A) Actual coefficient of performance can be calculated by the formula stated below

Actual COP = heat delivered/ work required

Actual COP = 2,000/600

Actual COP = 3.33

B) Th = High temperature = 80°C + 273 = 353K

Tl = Low temperature = 7°C + 273 = 280K

The theoretical maximum coefficient of performance can ve calculated by the formula

Theoretical COP = Th/(Th-Tl)

Theoretical COP = 353/(353-280)

Theoretical COP = 353/73

Theoretical COP = 4.84

3 0
3 years ago
Plate movement cause volcanoes to
Studentka2010 [4]
Is this a multiple choice question?
If not, well then the answer is that the volcano sort of sinks into the ground. Like it sort of subducts.
Hope this helped!!!:)
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7 0
3 years ago
Calculate the force of gravity on the 0.60- kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth
nignag [31]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the first object has a mass of m_1=0.60 kg, while the second "object" is the Earth, with mass m_2=5.97 \cdot 10^{24}kg. The distance of the object from the Earth's center is r=1.3 \cdot 10^7 m; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
F=G \frac{m_1m_2}{r^2}=(6.67\cdot 10^{-11}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=  1.41 N
5 0
3 years ago
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