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dexar [7]
3 years ago
6

A simple machine does work with one motion A. true B. false

Physics
1 answer:
zysi [14]3 years ago
4 0
Machine does work with one motion true. for example wind fan
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serg [7]
Where are the answer choice ?
3 0
3 years ago
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A rock thrown straight up takes 4.2 s to reach its maximum height what was its initial velocity
liubo4ka [24]

Consider the upward direction of motion as positive and downward direction of motion as negative.

a = acceleration due to gravity in downward direction = - 9.8 \frac{m }{s^{2}}

v₀ = initial velocity of rock in upward direction = ?

v = final velocity of rock at the highest point = 0 \frac{m }{s}

t = time to reach the maximum height = 4.2 sec

Using the kinematics equation

v = v₀ + a t

inserting the values

0 = v₀ + (- 9.8) (4.2)

v₀ = 41.2 \frac{m }{s}


8 0
3 years ago
Calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a princi
erica [24]

Answer:

L_max= 0

Explanation:

The formula for magnitude of maximum orbital angular momentum is given by

L_{max}= \sqrt{l(l+1)\bar{h}}

l= orbital quantum number

l= n-1

n= shell number or principal quantum number

for n=1 , l=0

therefore, L_{max}= \sqrt{0(0+1)\bar{h}}

L_max= 0

3 0
3 years ago
An ore car of mass 43000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 14 m lower vert
vagabundo [1.1K]

Answer:

x = 4.4719 m

Explanation:

For answer this we will use the law of the conservation of energy, where:

E_i = E_f

First, we will call:

E_i: the car in rest

E_f: when the spring is compressed

so:

E_i = E_f

Mgh= \frac{1}{2}KX^2

where M is the mass of the car, g the gravity, h the altitude, K is the constant of the spring and X is the spring compressed in stopping the ore car. So, replacing values, we get:

(43000)(9.8)(14)= \frac{1}{2}(5.9*10^5)X^2

solving for x:

x = 4.4719 m

4 0
3 years ago
The protons initially are located where the electric potential has a value of 7.60 MV and then they travel through a vacuum to a
DochEvi [55]

Answer:

(a) 3.82 x 10⁷ m/s

(b) 4.5 MV/m

Explanation:

(a)

ΔV = change in the electric potential as the proton moves = 7.60 x 10⁶ Volts

q = magnitude of charge on proton = 1.6 x 10⁻¹⁹ C

v = speed gained by the proton

m = mass of proton = 1.67 x 10⁻²⁷ kg

Using conservation of energy

Kinetic energy gained by proton = Electric potential energy

(0.5) m v² = q ΔV

inserting the values

(0.5) (1.67 x 10⁻²⁷) v² = (1.6 x 10⁻¹⁹) (7.60 x 10⁶)

v = 3.82 x 10⁷ m/s

(b)

d = distance over which the potential change = 1.70 m

Electric field is given as

E = ΔV/d

E = 7.60 x 10⁶/1.70

E = 4.5 x 10⁶ V/m

E = 4.5 MV/m

7 0
3 years ago
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