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Elina [12.6K]
3 years ago
9

An object with a mass of 1500kg accelerates 10.0m/s when unknown force is applied to it. What is the amount of force?

Physics
2 answers:
Hatshy [7]3 years ago
5 0

Answer:

<h3>The answer is 15000 N</h3>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1500 × 10

We have the final answer as

<h3>15,000 N</h3>

Hope this helps you

Sergio039 [100]3 years ago
5 0

Answer:

15000 N

Explanation:

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D) 0.32

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The computation of the thermal efficiency is given below:

Thermal efficiency is

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Therefore the last option is correct

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5 0
3 years ago
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What is the formula of Acceleration for mass and time​
GarryVolchara [31]

Answer:

a = m/t²

Explanation:

The Formula of Acceleration for mass and time

a = m/t²

where,

m = meter

t = time in (seconds)

The SI unit of acceleration is m/s² or ms⁻²

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5 0
3 years ago
A uniformly charged, straight filament 6 m in length has a total positive charge of 3 µC. An uncharged cardboard cylinder 1 cm i
Lorico [155]

Answer:

Part A : 5.) = 564.704 N*m²/C

Part B:  10.) = 179751.0 V/m

Explanation:

A) Applying Gauss'Law to the straight filament, using a cylindrical gaussian surface with the filament as the central axis of the surface, assuming that the electric field is normal to the surface (which means that no flux exist through the lids of the cylinder) and is constant at any point of the surface (except the lids where is 0), we can find the electric flux, as follows:

E*2*\pi *r*l = \frac{Qenc}{\epsilon 0} (1)

where:

r is the radius of the cylinder = 0.05 m

l is the length of the cylinder = 0.01 m

Qenc, is the net charge on the filament enclosed by the gaussian surface

ε₀ = 8.8542*10⁻¹² C²/N*m²

In order to find the value of Qenc, we need to find first the linear charge density, as follows:

\lambda = \frac{Q}{L} =\frac{+3e-6C}{6m}  = 5e-7 C/m

The net charge enclosed by the gaussian surface will be just the product of the linear change density λ times the length of the gaussian surface:

Qenc = \lambda * l = 5e-7C/m * 0.01 m = 5e-9 C

According Gauss ' Law, the net flux through the gaussian surface must be equal to the charge enclosed by the surface, divided by the permittivity of free space (in vacuum or air), as follows:

Flux = \frac{Qenc}{\epsilon 0} = \frac{5e-9C}{8.8542e-12 C2/N*m2} = 564.704 (N*m2)/C

which is the same as the option 5.

B)  Repeating the equation (1) from above:

E*2*\pi *r*l = \frac{Qenc}{\epsilon 0} (1)

we can solve for E, as follows:

E =  \frac{Qenc}{2*\pi*r*l* \epsilon 0} = \frac{5e-9C}{2*\pi*(0.05m)*(0.01m)*8.8542e-12 C2/N*m2} = 179751.0 V/m

which is the same as the option 10 of part B.

7 0
3 years ago
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