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Strike441 [17]
3 years ago
14

6 to the fourth power divided by 3 to the second power over 9

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

16

Step-by-step explanation:

(6^4/3^2)/9=16

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Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in
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5 People can be chosen  in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

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The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

nCr=\frac{(n)!}{(n-r)!(r)!}

So here , n =13  and r=5 ,  

So after putting the value  of n and r , the equation will be

13C_5=\frac{(13)!}{(13-5)!(5)!}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 )}{((5 \times4 \times3 \times2 \times1)}

13C_5=\frac{154440}{120}

13C_5= 1287

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