Answer:
(a) Step 2. 9x -12 = 13 +2x
Step-by-step explanation:
The distributive property says a factor outside parentheses multiplies each term inside parentheses. It is an error to do addition of the factor, or to miss multiplying a term.
In Step 2 of this "solution", the factor of 3 is erroneously <em>added</em> to each coefficent inside parentheses. It should be <em>multiplied</em>.
Correct Step 2: 9x -12 = 13 +2x
__
The rest of the solution should be ...
Step 3: 9x -2x = 13 +12
Step 4: 7x = 25
Step 5: x = 25/7
___
<em>Check</em>
3(3(25/7) -4) = 8 + 2(25/7) +5
3((75 -28)/7) = 13 +50/7
141/7 = 141/7 . . . . . answer checks OK
Answer:
A. 24
Step-by-step explanation:
n Over 54 EndFraction = StartFraction 4 Over 9 EndFraction
n/54 = 4/9
Cross product
n * 9 = 54 * 4
9n = 216
n = 216/9
n = 24
A. 24
Check:
n/54 = 4/9
24 / 54
Divide through by 6
= 4/9
Answer:
B.
Step-by-step explanation:
The vertical line test is what I used to test this.
Answer:
y(s) = 
we will compare the denominator to the form 

comparing coefficients of terms in s
1
s: -2a = -10
a = -2/-10
a = 1/5
constant: 

hence the first answers are:
a = 1/5 = 0.2
β = 5.09
Given that y(s) = 
we insert the values of a and β
= 
to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A
5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)
-52 = B(26)
B = -52/26 = -2
to get A lets substitute s=0.4
5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)
-51 = 0.2A - 52.08
0.2A = -51 + 52.08
A = -1.08/0.2 = 5.4
<em>the constants are</em>
<em>a = 0.2</em>
<em>β = 5.09</em>
<em>A = 5.4</em>
<em>B = -2</em>
<em></em>
Step-by-step explanation:
- since the denominator has a complex root we compare with the standard form

- Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
- substitute the values gotten into the function
- Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
- after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above
Thanks...
Answer:
x = -3 and x = 1/2
Step-by-step explanation:
To find the solutions to
2x² + 5x - 3 = 0
we can use the quadratic formula, as follows:






