Please help me with question B.
1 answer:
You might be interested in
Answer:
- The maximum height reached by the ball is 45.92 m
- Time taken to fall down to half of its height is 2.2 s
Explanation:
Given;
initial velocity of the ball, u = 30 m/s
final velocity of the ball at the highest point, v = 0
The maximum height reached by the ball is calculated as;
v² = u² - 2gh
where;
h is the maximum height reached by the ball
0 = 30² - (2 x 9.8)h
19.6h = 900
h = 900 / 19.6
h = 45.92 m
Time taken to fall to half of its height is calculated as;
when falling down, the final velocity v becomes the initial velocity = 0.
Apply the following kinematic equation;
h = ut + ¹/₂gt²
h = 0 + ¹/₂gt²
h = ¹/₂gt²
where;
h = 45.92 m is the maximum height reached
half of h = 45.92 / 2 = 22.96 m
22.96 = ¹/₂gt²
Answer:
B = 0.135T
Explanation:
To find the magnitude of the magnetic field you use the following formula, for the torque produced by a magnetic field B in a loop:
(1)
τ: torque = 1.51*10^-5 Nm
I: current = 2.47mA = 2.47*10^-3 A
B: magnitude of the magnetic field
A: area of the loop = 4.97cm^2 = 4.97(10^-2m)^2=4.97*10^-4m^2
N: turns = 181
θ: angle between B and the magnetic dipole (same as the direction of the normal to the plane)
You replace the values of the parameters in (1). Furthermore you do B the subject of the formula: