Answer:
There are several options that the teacher can use to incorporate the concept into students' understanding.
Explanation:
1. The students can draw all the plants that they know.
2. Children can be asked to bring the flowers to school so that they can identify the plants themselves.
3. The children can plat the flowers in makeshift pots and then take the best plants and transplant them in the garden or elsewhere.
4. The children can take occasional trips and observe and record any changes to the plants.
4. The teacher can ask the students to draw the flowers and emphasize on the productive parts like the stamens, leaves, pistils, stems.
The question to the above information is;
What is the best use of an atomic model to explain the charge of the particles in Thomson's beams?
Answer;
An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to remove.
Explanation;
-Atoms are comprised of a nucleus consisting of protons (red) and neutrons (blue). The number of orbiting electrons is the same as the number of protons and is termed the "atomic number" of the element.
J.J. Thomson discovered the electron. Atoms are neutral overall, therefore in Thomson’s ‘plum pudding model’:
- atoms are spheres of positive charge
- electrons are dotted around inside
Answer:
F= 5195.625 N
Explanation:
To obtain the force needed to hold the child, we need to know the aceleration in which the car is breaking.
Aceleration is equal to velocity divided by the time of breaking
In international system, velocity [m/s] is
v= (62 mi/h)*(1609 m/mi)*(1 h/3600 s)
v= 27.71 m/s
Now, we part the velocity by the time that is 0.08 seconds
a= v/t= (27.71 m/s)/(0.08 s)
a= 346.375 m/
The force in agreement with the Newton's second law is
F=m*a = 15 Kg*346.375 m/
F= 5195.625 N
(Note: 1 N = 1 Kg*m/
)
I would say true. If you are calculating using vectors than it would need both...
Answer:
θ '= 4975 rev
Explanation:
For this exercise let's use the relationship between work and the change in kinetic energy
W = ΔK
the expression for work is
W = - τ Δθ
where the negative sign indicates that the torque is in the opposite direction to rotation
kinetic energy
K = ½ I w²
we substitute
- τ Δθ = 0 - ½ I w²
θ =
if we approach the rotor to a cylinder with an axis of rotation through its center
I = ½ m r²
we substitute
θ = ½ (½ m r²)
How the measurements are in the English system, the weight
W = m g
m = W / g
let's reduce to the english system
w = 3600 rev / min (2pi rad / 1rev) (1 min / 60s) = 376.99 rad / s
r = 9 in (1 ft / 12in) = 0.75 ft
let's calculate
m = 125/32 = 3.91 slug
θ = ¼ 3.91 0.75² 376.99² / 2.5
θ = 3.126 10⁴ rad
let's reduce to revolutions
θ’= 3.126 10⁴ rad (1rev / 2π rad)
θ’= 4974.9 rev
θ '= 4975 rev