The correct statement is:
The dust particle will move to a larger orbit and orbit the Sun in more than 1 year.
In fact, the dust particle has smaller mass than the Earth, therefore the gravitational attraction exerted by the Sun on the dust will be smaller, according to the formula of the gravitational force:
where G is the gravitational constant, MS is the Sun mass, m is the mass of the Earth (at first) and then of the dust particle (later), and r is the distance from the Sun. When we replace the Earth with the dust particle we see that m decreases, so the gravitational force F decreases, and the particle will move to a larger orbit. Then its orbital period will increase, according to the third law of Kepler, which states that the square of the orbital period is proportional to the cube of the orbital radius:
therefore, since the orbit is larger, the orbital period is greater.
- Initial velocity=20m/s
- Final velocity=0m/s(As the car stops)
- Acceleration=-8m/s^2
- Distance=s=26m
We need to verify the thrid equation of kinematics here
The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .
There are different kinds of conductors, most notably electrical and thermal conductors. But they are often inclusive of each other (electrical conductors are typically good thermal conductors).
A conductor transmits something through its body with high efficiency while an insulator does not transmit very well. In the case of electricity, a conductor transmits electrical energy between two points while an insulator blocks the flow of electricity.
Two examples of conductors are copper and silver. Two examples of insulators are wood and styrofoam.
Answer:
The magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.
Explanation:
Given;
Radius of circular loop, R = 3.00 cm = 0.03 m
Current in the loop, I = 12.0 A
Magnetic field at the center of circular loop is given as;
B = μ₀I / 2R
Where;
μ₀ is constant = 4π x 10⁻⁷ T.m/A
R is the radius of the circular loop
I is the current in the loop
Substitute the given values in the above equation and calculate the magnitude of the magnetic field;
B = (4π x 10⁻⁷ x 12)/ 0.03
B = 5.0272 x 10⁻⁴ T
Therefore, the magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.
To solve this problem we will apply the concepts of equilibrium and Newton's second law.
According to the description given, it is under constant ascending acceleration, and the balance of the forces corresponding to the tension of the rope and the weight of the elevator must be equal to said acceleration. So
Here,
T = Tension
m = Mass
g = Gravitational Acceleration
a = Acceleration (upward)
Rearranging to find T,
Therefore the tension force in the cable is 10290.15N
