VINILLE Which ordered pair is a solution of the equation? y + 5 = 2(x+1)

Mathematics

1 answer:

madam [21]3 years ago

6 0

Answer:

tje ordered pair for y+5=2(x+1)

is x=(1.5,0) and y=(0,-3)

Step-by-step explanation:

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Which line has the same slope as the line passing through (- 4, -1) and (-1, 8)

Troyanec [42]

The slope is [ 8 - (-1) ] / [ -1 - (-4) ] = 9 / 3 = 3;

The line has the equation: y - 8 = 3( x + 1);

y - 8 = 3x + 3;

y = 3x + 11.

7 0

3 years ago

How do you answer this?

SVEN [57.7K]

$(m^{-2})^5=m^{-2\cdot5}=m^{-10}$

$x^2+3x-10=\\
x^2+5x-2x-10=\\
x(x+5)-2(x+5)=\\
(x-2)(x+5)$

4 0

3 years ago

Read 2 more answers

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$