Cellular respiration is also a catabolic process because it breaks the small molecules from digestion into even smaller ones as ATP is created. These are both very important processes, because ATP is what your cells use to produce body heat, move your muscles, and other essential bodily functions.
<h2>Cell Cycle
</h2>
Explanation:
Eukaryotes grow and divide by cell cycle.
The main parts of a cell cycle are an ordered series of events – Gap 1 or G1 phase, Synthesis or S phase, Gap 2 or G2 phase, and the mitosis or M phases.
Interphase period (G1, S, G2 phases) - cell grows by size, duplicates its content, replicates its DNA, and finally prepares for mitotic cell division
.
Mitosis and cytokinesis - formation of two identical daughter cells
Cell cycle is regulated by regulatory or restrictive checkpoints in the cell cycle which are activated with detection of a defective DNA.
Proliferation of undesired or cells with defective DNA like in case of tumor cells is controlled by the action of suppressing agents like p53 and cyclins.
The tumor suppressor gene protein p53 prohibits division of tumor cells. Cyclins regulate cell cycle by activation of the enzyme cyclin-dependent kinase.
Gastrointestinal stromal tumor (GIST)
Stomach cancer can also be refers to as
gastric cancer, thus, stomach cancer develop from the inner lining of the
stomach. However, tumor produced by the gastric cancer is known as
gastrointestinal stromal tumor (GIST). Some of these tumor are non-cancerous while
other are cancerous and they can be found anywhere in the digestive tract.
The term 2pq represented in the hardy-weinberg equation is the frequency of heterozygotes and is denoted as option D.
<h3>What is Hardy-weinberg equation?</h3>
This mathematical equation is used to calculate the genetic variation of a population at equilibrium and can be seen below:
p² + 2pq + q² = 1
where
p² is dominant homozygous frequency (AA)
2pq is heterozygous frequency (Aa)
q² is recessive homozygous frequency (aa).
The 2pq can be seen as the heterozygous frequency which is therefore the reason why option D which is frequency of heterozygotes was chosen as the most appropriate choice.
Read more about Hardy-weinberg equation here brainly.com/question/5028378
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