The percentage of mechanical energy of the oscillator lost in each cycle is 5.91 %.
The formula for mechanical energy in an oscillator is given by
E = 1/2 kA²
It is the sum of elastic potential energy and kinetic energy.
Amplitude is nothing but the maximum displacement moved by a point on vibrating body.
It is given that the amplitude A decreases by 3%, then
(E₂ - E₁) / E₁ = [1/2 k (A₂²- A₁²)] /(1/2 k A₁²) = (A₂²- A₁²)/ A₁² = (97² - 100²)/ 100²
⇒ 5.91% of the mechanical energy is lost in each cycle.
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Answer:
v = 1.2 m/s
Explanation:
The wavelength of the waves is given as the horizontal distance between the crests:
λ = wavelength = 5.5 m
Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:
T = Time Period = 2(2.3 s) = 4.6 s
Now, the speed of the wave is given as:
where,
v= speed of wave = ?
f = frequency of wave = 
Therefore,
<u>v = 1.2 m/s</u>
B. A sandbar is formed by water. A sand dune is formed by wind.
Electrons - have a negative charge and orbit the nucleus
Protons - have a positive charge and are located in the nucleus
Neutrons - have no charge and are also located in the nucleus
