Two inductors, L1 and L2, are in parallel. L1 has a value of 25 mH and L2 a value of 50 mH. The parallel combination is in serie s with L3, a 20 mH coil. The entire combination is across an ac source of 60 Vrms at 300 kHz. The total rms current is
1 answer:
Answer:
Explanation:
For parallel inductors ,
For series combination
Total inductance
= 16.67 + 20
= 36.67 mH .
reactance of total inductance at 300 kHz
= ω where ω is angular frequency
= 2πf
= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³
= 69.1 x 10³ ohm
Total rms current = Vrms / reactance
= 60 / 69.1 x 10³ A
= .87 x 10⁻³ A
= .87 mA
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