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Gnoma [55]
3 years ago
13

At the same temperature, two wires made of pure copper have different resistances. The same voltage is applied at the ends of ea

ch wire. The wires may differ in
Physics
1 answer:
Semmy [17]3 years ago
6 0

Answer:

Explanation:

As we know that the resistance of the wire is directly proportional to the length of wire and inversely proportional to the area of crossection of the wire.

As the material is copper for both the wires so the resistivity is same and the voltage is also same. As their resistance is different it means either length is different or the area of crossection is different.

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5. An ion consist of 12 electrons and 11 proton. What is the charge<br> on the ion?
sammy [17]

Answer:

-1

Explanation:

Electrons have a negative charge and protons have a positive charge. (+11) + (-12) = -1

5 0
3 years ago
You have a light spring which obeys Hooke's law. This spring stretches 2.92 cm vertically when a 2.70 kg object is suspended fro
ehidna [41]

(a) 907.5 N/m

The force applied to the spring is equal to the weight of the object suspended on it, so:

F=mg=(2.70 kg)(9.8 m/s^2)=26.5 N

The spring obeys Hook's law:

F=k\Delta x

where k is the spring constant and \Delta x is the stretching of the spring. Since we know \Delta x=2.92 cm=0.0292 m, we can re-arrange the equation to find the spring constant:

k=\frac{F}{\Delta x}=\frac{26.5 N}{0.0292 m}=907.5 N/m

(b) 1.45 cm

In this second case, the force applied to the spring will be different, since the weight of the new object is different:

F=mg=(1.35 kg)(9.8 m/s^2)=13.2 N

So, by applying Hook's law again, we can find the new stretching of the spring (using the value of the spring constant that we found in the previous part):

\Delta x=\frac{F}{k}=\frac{13.2 N}{907.5 N/m}=0.0145 m=1.45 cm

(c) 3.5 J

The amount of work that must be done to stretch the string by a distance \Delta x is equal to the elastic potential energy stored by the spring, given by:

W=U=\frac{1}{2}k\Delta x^2

Substituting k=907.5 N/m and \Delta x=8.80 cm=0.088 m, we find the amount of work that must be done:

W=\frac{1}{2}(907.5 N/m)(0.088 m)^2=3.5 J

5 0
3 years ago
What is the mass of a 2 kg object on the Earth and on the moon?
zubka84 [21]

Answer:

Same

Explanation:

Mass is the quantity of matter in a certain object.

WHEREVER you take a 2kg object, the mass will remain 2kg. All that changes is the Weight ..Weight the force which the centre of a Planet uses to pull everything towards itself.

On earth, it is 9.81 whereas on the Moon it is 1.6

7 0
3 years ago
For how long should a force of 100N act on a body of mass 20kg at rest so that it acquires a velocity of 100m/s?​
julia-pushkina [17]

Answer:

20 seconds

Explanation:

7 0
3 years ago
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Where does fission regularly occur and what kind of energy is produced?
WARRIOR [948]
Which one are you talking about bc there's a couple
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3 years ago
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