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Zielflug [23.3K]
3 years ago
11

HELP ME PLEASE WILL GIVE BRAINLEST ANSWER

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

402 cubic squared

Step-by-step explanation:

so you have a triangle and rectangle shapes so find area of each on and add them

10 x 28 = length times with = 280

28-12 = 16 and 24 - 10 = 14

14 x 16 x 1/2 = base times hight times 1/2  = 122

122 + 280 = 402

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How many square roots does -625 have?
notka56 [123]
It has 2 square roots
4 0
3 years ago
write the equation of a line that is parallel to the line 2y+x=9 and passes through the point (4,-7)​
Marrrta [24]

Answer:

y=-(1)/(2)x-5

Step-by-step explanation:

4 0
4 years ago
Consider the probability that greater than 77 out of 131 computers will crash in a day. Assume the probability that a given comp
sweet-ann [11.9K]

Answer:

A Normal approximation to binomial cannot be applied to approximate the distribution of <em>X</em>, the number of computer crashes in a day.

Step-by-step explanation:

Let <em>X</em> = number of computers that will crash in a day.

The probability of a computer crashing in a day is, <em>p </em>= 0.99.

A random sample of <em>n</em> = 131 is selected.

A random computer crashing in a day is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 131 and <em>p</em> = 0.99.

But the sample size is quite large, i.e. <em>n</em> > 30.

So the distribution of <em>X</em> can be approximated by the normal distribution if the following conditions are fulfilled:

  • np ≥ 10
  • n(1 - p) ≥ 10

Check whether the conditions satisfy or not:

np=131\times 0.99=129.69>10\\n(1-p)=131\times (1-0.99)=1.31

The second condition is not fulfilled.

A Normal approximation to binomial cannot be applied to approximate the distribution of <em>X</em>, the number of computer crashes in a day.

6 0
3 years ago
Question 2 of 10<br> 2 Points<br> What is the solution to this equation?<br> 5x + 15 + 2x = 24 + 4x
Dafna1 [17]

Answer:

Step-by-step explanation:

5x + 15 + 2x = 24 + 4x

7x + 15 = 24 + 4x

7x - 4x = 24 - 15

3x = 9

x = 9/3

x = 3 <====

3 0
3 years ago
Read 2 more answers
Iodine-131, a radioactive substance that is effective in locating brain​ tumors, has a​ half-life of only 8 days. A hospital pur
Aloiza [94]

The mass of substance left after 7 days is 13.09 g

The mass of substance left, N is given by

N = N₀exp(-λt) where λ = decay constant and N₀ = initial mass of substance present = 24 g and t = time

Also, λ = 0.693/t' where t' = half-life of iodine = 8 days

So, λ = 0.693/t'

λ = 0.693/8

λ = 0.086625/day

Since the mass of substance left is N = N₀exp(-λt) and we require the mass of substance after t = 7 days,

N = N₀exp(-λt)

N = 24 gexp(-0.086625/day × 7 days)

N = 24 gexp(-0.606375)

N = 24 g × 0.5453

N = 13.09 g

So, the mass of substance left after 7 days is 13.09 g

Learn more about radioactive decay here:

brainly.com/question/23705307

7 0
3 years ago
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