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Debora [2.8K]
3 years ago
12

Josh practices free throws during basketball practice on Monday and Tuesday. On Monday, he attempts 15 free throws and 6 basketb

alls went in the basket. Over both days, Josh wants at least 80% of his balls to go in the basket. If he makes every free throw on Tuesday, what is the minimum number of free throws required on Tuesday to reach his goal?
Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

he has to make 12 shots

Step-by-step explanation:

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Answer:

The answer is "3".

Step-by-step explanation:

\texttt{Given graph equation: } \\\\\bold{\Rightarrow f(x)=\frac{4}{x^2-6x+9} }

\bold{\ interval:  (a,\infty)}

differentiate the function f(x):

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Formula:

\bold{\frac{d}{dx} \frac{v}{u}= \frac{u \frac{d}{dx} v- v\frac{d}{dx}u }{u^2}}

\Rightarrow f'(x) = \frac{d }{dx}(\frac{4}{x^2-6x+9})\\\\\\\Rightarrow f'(x) = \frac{d }{dx}(\frac{(x^2-6x+9) \frac{d}{dx} 4- 4\frac{d}{dx}(x^2-6x+9) }{(x^2-6x+9)^2})\\\\\\\Rightarrow f'(x) = \frac{d }{dx}(\frac{(x^2-6x+9) \times 0 - 4(2x-6) }{(x^2-6x+9)^2})\\\\\\\Rightarrow f'(x) =  \frac{- 4(2x-6)}{(x^2-6x+9)^2}\\\\\\\Rightarrow  \frac{- 4(2x-6)}{(x^2-6x+9)^2}=0\\\\\Rightarrow - 4(2x-6)=0\\\\\Rightarrow  8x-24=0\\\\\Rightarrow  8x=24\\\\\Rightarrow  x=\frac{24}{8}\\\\\Rightarrow  x=3\\\\

since the value of x in: (-3 ,\infty) \ \  and  \ \ (3, \infty) and f'(x). So, the value of a is 3

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