Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by
![E = \frac{r}{p}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Br%7D%7Bp%7D)
In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
The answer is 0.5.
X is the input and f(x) is the output. Between -3 and -2 the difference is 0.5. Because it goes from -0.5 to 1
Answer:
-1 -3i
Step-by-step explanation:
It is unusual to have two imaginary terms grouped together like this. Taking the question at face value, we treat i as though it were a variable, and collect terms in the usual way.
(-2i +3i) +(-1 -4i) = i(-2+3-4) -1 = -1 -3i
Answer:
The answer is C and D.
Step-by-step explanation:
(-4)^1/2 = undefined
(-16)^1/4 = undefined
(-32)^1/5 = -2
(-8)^1/3 = -2
Answer:
b = -57/10
Step-by-step explanation:
Let's first distribute everything out:
-8(1 + 5b) = -8 * 1 + (-8) * 5b = -8 - 40b
2(86 - 1) = 2 * 85 = 170
So, we have:
-8 - 40b - 170 = 50
-40b - 178 = 50
-40b = 50 + 178 = 228
b = -228/40 = -57/10
Thus, the answer is b = -57/10.
Hope this helps!