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ozzi
3 years ago
15

One source of the isotope is reprocessed nuclear reactor fuel. how many protons and neutrons does the 106ru nucleus contain?

Chemistry
1 answer:
mash [69]3 years ago
5 0
Protons= Atomic Number (44).
Neutrons= Atomic Mass (106) - Atomic Number (44) = 62. 
Therefore RUTHENIUM-106 has 44 protons and 62 neutrons. 
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write a sentence about the evidence for plate tectonics yielded from earthquakes,valcanoes, and age of sea floor.
gulaghasi [49]

Answer:

Fossils, Glaciers, Coastlines.

Explanation:

Evidence of plate tectonic theory are fossils, fossils of the same species were found oceans apart. also glaciers evidence of glaciers were found in places with warm climates. coastlines coastlines look like they fit in a puzzle.

5 0
3 years ago
Find the volume of an object that has a mass of 20g and density of 184 glcm
expeople1 [14]
Volume= Mass/ Density= 20/184
= 0.108 cubic cm
8 0
3 years ago
During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. S
Kay [80]

<u>Answer:</u> The below calculations proves that the rate of diffusion of ^{235}UF_6 is 0.4 % faster than the rate of diffusion of ^{238}UF_6

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

Molar mass of ^{235}UF_6=349.034348g/mol

Molar mass of ^{238}UF_6=352.041206g/mol

By taking their ratio, we get:

\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{M_{(^{238}UF_6)}}{M_{(^{235}UF_6)}}}

\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{352.041206}{349.034348}}\\\\\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\frac{1.00429816}{1}

From the above relation, it is clear that rate of effusion of ^{235}UF_6 is faster than ^{238}UF_6

Difference in the rate of both the gases, Rate_{(^{235}UF_6)}-Rate_{(^{238}UF_6)}=1.00429816-1=0.00429816

To calculate the percentage increase in the rate, we use the equation:

\%\text{ increase}=\frac{\Delta R}{Rate_{(^{235}UF_6)}}\times 100

Putting values in above equation, we get:

\%\text{ increase}=\frac{0.00429816}{1.00429816}\times 100\\\\\%\text{ increase}=0.4\%

The above calculations proves that the rate of diffusion of ^{235}UF_6 is 0.4 % faster than the rate of diffusion of ^{238}UF_6

3 0
3 years ago
Given the reaction represented by the balanced equation:
user100 [1]

Answer:

mass of CHF_3 = 1/3 \times 9.47 \times 70 =220.97g

Explanation:

CH_4(g)+3F_2(g)->3HF(g)+CHF_3

As given in the question that methane(CH_4) is taken excess amount

mass of CHF_3 depend only on mass of fluorine

mass of F_2 =180 g

mole of F_2=\frac{180}{19} =9.47

3 mole of F_2 gives 1 mole of CHF_3

so 1 mole will give \frac{1}{3} mole of CHF_3

therefore,

9.47 mole of F_2 will give \frac{1}{3}  \times 9.47 mole of CHF_3

mass of CHF_3 = 1/3 \times 9.47 \times 70 =220.97g

7 0
3 years ago
The stock concentration of NaOH is 0.5M. 0.5M = 0.500mol/1.0L.
valentinak56 [21]

Answer:a) 0.1 mole. b) 4g. c) 2% d)  196 mL

Explanation: in 200mL , 0.1mole

mw NaOH = 40g/mol —> 4g in 0.1 mole

4g in 200mL so 2g in 100mL

density NaOH = 1g/mL so if 4g in 200 mL,  4mL , 196 mL water

5 0
3 years ago
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