M1 = 17.45 M
M2 = 0.83 M
V2 = 250 ml
M1. V1= M2. V2
V1 = (M2. V2)/M1 = (0.83× 250)/ 17.45= 11.89 ml
It takes 21.3 days
<h3>Further explanation</h3>
Given
5 hr = 8 kg Alcohol
Required
Days to consume 1000 kg of glucose
Solution
Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,
C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂
mol ethanol :

moles of glucose to produce 108.7 moles ethanol :

54.35 moles = 5 hours
moles of 1000 kg of glucose :

So for 5555.5 moles, it takes :

Based on the standards of units conversion, to convert from micrometer to meter, we multiply by 10^-6.
Since we there is a square (10^2) to consider, then to convert from micrometer squared to meter squared, we will multiply by (10^-6)^2 as follows:
1.5 <span>μm2 = 1.5 x (10^-6)^2 = 1.5 x 10^-12 meter sqaures</span>
The answer would be b) GAS
Answer:
1290 atm
Explanation:
P1V1=P2V2
P2= (P1V1)/V2
P2=(2.15 atm * 750 mL)/(1.25 mL)
P2=1290 atm