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zubka84 [21]
3 years ago
12

All the nonmetals have some similar physical properties. True False

Chemistry
2 answers:
QveST [7]3 years ago
7 0
I think that the answers is false

miss Akunina [59]3 years ago
4 0
This is false, all non metals have different physical properties.
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A 0.229-g sample of an unknown monoprotic acid is titrated with 0.112 m naoh. the resulting titration curve is shown here. part
Kazeer [188]
It would be 0.341 because if you add 0.229 and 0.112 it will be 0.341
4 0
3 years ago
which term is used when sugar is completely dissolved in water                                                                 
GaryK [48]
The term which is used is homogeneous.
when sugar is completely dissolved in the water, the mixture or solution homogeneous, both in same phase and same uniform texture that is liquid.
There two types of mixtures are heterogeneous and homogeneous in different phases.
If sugar is not completely dissolved in water and you see the crystals of sugar in water, then the solution will be heterogeneous.
3 0
3 years ago
Find the volume of 0.100M hydrochloric acid necessary to react completely with 1.51g Al(OH)3.
shtirl [24]
Reaction equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Moles of Al(OH)₃:
moles = mass/Mr
= 1.51 / (27 + 17 x 3)
= 0.019
Molar ratio Al(OH)₃ : HCl = 1 : 3
Moles of HCl required = 0.019 x 3
=0.057
concentration = moles/volume
volume = 0.057 / 0.1
= 0.57 dm³
= 570 ml
3 0
3 years ago
Pls halp. i give brainliest to 1st correct answer
Kruka [31]

Answer:

C is correct

Explanation: Heat describes the transfer of thermal energy between molecules within a system and is measured in Joules. Heat measures how energy moves or flows. ... Temperature describes the average kinetic energy of molecules within a material or system and is measured in Celsius (°C), Kelvin(K), Fahrenheit (°F), or Rankine (R)

4 0
2 years ago
What is the molarity of a solution that contains 148g NaOH in 4.00 L solution? a 0.925 M b 0.0253 M c 0.459 M d 1.363 M
Anton [14]

Answer:

M = 0,925

Explanation:

n= mass/Molecular Weight

n = 148g / 39,99 (g/mol)

n= 3,7mol

M= n/Volumen(L)

M= 3,7mol/4L

M=0,925

8 0
3 years ago
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