False.
False.
True.
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Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,

Where, m is mass of iron
s is specific heat of iron
d T is change in temperature in celcius

If
1 cal = 4.2 J
Then,

Thus 0.389 k cal of enrgy is required by a 15.6 g Fe to reach to 355 C^0
N(H₂O)=1g÷18g/mol=0,055mol
N(H₂O)=0,055mol · 6·10²³ 1/mol (Avogadro number)= 3,33·10²² molecules.
According to the balanced reaction equation:
2KClO3→ 2KCl + 3O2
from this equation, we can see that the molar ratio between KCl & O2 is 2 : 3
so, 2 moles of KCl will need 3 moles of O2
∴ 7.16 moles of KCl will need X moles of O2
∴number of moles of O produced = 7.16 * 3 / 2
= 10.74 moles