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Brrunno [24]
3 years ago
10

A student takes an object with an accepted mass of 120.0 grams and masses it on their

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

<h2>The answer is 5.25 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual mass = 120 g

error = 120 - 113.7 = 6.3

The percentage error is

P (\%) =  \frac{6.3}{120}  \times 100 \\  = 5.25

We have the final answer as

<h3>5.25 %</h3>

Hope this helps you

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A certain gas is present in a 15.0 LL cylinder at 2.0 atmatm pressure. If the pressure is increased to 4.0 atmatm the volume of
Helga [31]

Explanation:

According to Boyle's law,  pressure of a gas is inversely proportional to its volume at constant temperature and moles.

Mathematically,       P = \frac{k}{V}

where,     k = proportionality constant

Also, formula for initial pressure and volume is as follows.

              P_{i} = \frac{k_{i}}{V_{i}}

or,           k_{i} = P_{i} \times V_{i}

                          = 2 atm \times 15 L

                          = 30 atm L

Now, we will calculate the value of k_{f} as follows.

             k_{f} = P_{f} \times V_{f}

                         = 4 atm \times 7.5 L

                         = 30 atm L

Hence, as k_{i} = k_{f} this means that it signifies that gas obeys boyle's law.

6 0
4 years ago
Hydrogen and nitrogen react to form ammonia according to the reaction, 3 H2 + N2 â&gt; 2 NH3. If 4.0 moles of H2 with 2.0 moles
Debora [2.8K]

Answer:

d) 2.7 mol

Explanation:

  • 3 H2 + N2 → 2 NH3

limit reagent is H2:

∴ Mw H2 = 2.016 g/mol

∴ Mw N2 = 28.0134 g/mol

⇒ moles NH3 = (4.0 moles H2)×(2 mol NH3/3mol H2)

⇒ moles NH3 = 2.666 mol

⇒ moles NH3 ≅ 2.7 mol

5 0
3 years ago
How many formula units are found in 2.10 gram of Mgo? (No units<br> needed.)
disa [49]

Answer:

84.63924

Explanation:

one moles equals 40.30440

8 0
3 years ago
Diagrama de lewis for ncl3
IRISSAK [1]

The diagram should show for ncl3

4 0
3 years ago
How much heat is released when 1.4 mol of hydrogen fluoride are produced?
Assoli18 [71]

Answer:

+375.2 KJ.

Explanation:

The balanced equation for the reaction is given below:

H₂ + F₂ —> 2HF ΔH = +536 KJ

From the balanced equation above,

2 moles of HF required +536 KJ .

Finally, we shall determine the heat required to produce 1.4 mol of hydrogen fluoride, HF. This is illustrated below:

From the balanced equation above,

2 moles of HF required +536 KJ .

Therefore, 1.4 moles of HF will require = (1.4 × 536)/2 = +375.2 KJ

Thus, +375.2 KJ of heat energy is required.

7 0
3 years ago
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