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Nata [24]
3 years ago
11

A student increases the temperature of a balloon from 278 K to 231 K. Assuming constant pressure, what should the new volume of

the balloon be?
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
4 0
I'm assuming that you're working with gas laws here. This would be relating to Charles's Law which states that the volume of a gas is proportional to the temperature when pressure is held constant (or that when temperature increases, the volume increases). The formula looks like this: 
\frac{V1}{T1}= \frac{V2}{T2}. 

You're given T1=278 K and T2=231 K. You need a V1 (which usually is given to you). Plug the numbers into the formula and solve for V2. Good luck!
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What cell part is NOT found in all cells?
elena-s [515]

Answer:

heart I think also I'm so sorry if I get you this wrong I think membrane not sure tell me what was the right answer but I think membrane.

3 0
3 years ago
How many moles of SO2 are required to produce 0.45 mole CS2?
Kaylis [27]

Answer: The moles of carbon needed will be, 13.8 moles

Explanation: Moles of  = 5.52 mole

Now we have to calculate to moles of carbon.

The given balanced chemical reaction is,

From the balanced chemical reaction, we conclude that

As, 2 mole of  react to give 5 moles of carbon

So, 5.52 mole of  react to give  moles of carbon

Therefore, the moles of carbon needed will be, 13.8 moles

4 0
3 years ago
Read 2 more answers
A sample of gas occupies 10 L at STP. What
puteri [66]

Pressure is 5.7 atm

<u>Explanation:</u>

P1 = Standard pressure = 1 atm

P2 = ?  

V1 = Volume = 10L

V2= 2.4L

T1 = 0°C + 273 K = 273 K

T2 = 100°C + 273 K = 373 K

We have to find the pressure of the gas, by using the gas formula as,

$\frac{P 1 V 1}{T 1}=\frac{P 2 V 2}{T 2}

P2 can be found by rewriting the above expression as,

$P 2=\frac{P 1 \times V 1 \times T 2}{T 1 \times V 2}

Plugin the above values as,

$P 2=\frac{1 \text {atm} \times 10 L \times 373 \mathrm{K}}{273 \mathrm{K} \times 2.4 \mathrm{L}}=5.7 \text { atm }

4 0
3 years ago
uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read
OverLord2011 [107]

Answer:

18.91 ml

Explanation:

Initial volume of base=2.04 ml

Final volume of base = 20.95 ml

Volume of base used= 20.95 - 2.04 = 18.91 ml

Note that the volume of base used is obtained as the difference between the final and initial volume of base, hence the answer given above.

5 0
3 years ago
Determine how many moles are present in 523.46g of glucose, c6h12o6
Galina-37 [17]

1 mole C6H12O6 -------------- 180.15 g
? moles C6H12O6 ------------ 523.46 g

523.46 x 1 / 180.15 => <span>2.905 moles</span>
8 0
3 years ago
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