A student increases the temperature of a balloon from 278 K to 231 K. Assuming constant pressure, what should the new volume of
1 answer:
I'm assuming that you're working with gas laws here. This would be relating to Charles's Law which states that the volume of a gas is proportional to the temperature when pressure is held constant (or that when temperature increases, the volume increases). The formula looks like this:
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You're given T1=278 K and T2=231 K. You need a V1 (which usually is given to you). Plug the numbers into the formula and solve for V2. Good luck!
You're given T1=278 K and T2=231 K. You need a V1 (which usually is given to you). Plug the numbers into the formula and solve for V2. Good luck!
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Answer:
a. 3-methylbutan-2-ol
b. 2-methylcyclohexan-1-ol
Explanation:
For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>
In the case of <u>2-methyl-2-butene</u>, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore <u>the "OH" will be added to carbon three</u> producing <u>3-methylbutan-2-ol</u>.
For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.
See figure 1
I hope it helps!
