A student increases the temperature of a balloon from 278 K to 231 K. Assuming constant pressure, what should the new volume of
1 answer:
I'm assuming that you're working with gas laws here. This would be relating to Charles's Law which states that the volume of a gas is proportional to the temperature when pressure is held constant (or that when temperature increases, the volume increases). The formula looks like this:
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You're given T1=278 K and T2=231 K. You need a V1 (which usually is given to you). Plug the numbers into the formula and solve for V2. Good luck!
You're given T1=278 K and T2=231 K. You need a V1 (which usually is given to you). Plug the numbers into the formula and solve for V2. Good luck!
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In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
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Answer: The correct option is
Explanation:
Atomic mass of calcium ,Ca = 40.07 g/mol
Atomic mass of chlorine ,Cl = 35.5 g/mol
Molar mass of :
= (Atomic mass of Ca+2 × (Atomic mass of Cl))
= (40.07 g/mol + (2 × 35.5))=111.07 g/mol
Hence, the correct option is